Answer:
Step-by-step explanation:
<u>Solving quadratic equation:</u>
- 5x² - 8x + 5 = 0
- x = (-b ± √b²-4ac)/2a
- x = (8 ± √8²-4*5*5)/2*5
- x = (8 ± √64-100)/10
- x = (8 ±√-36)/10
- x = (8 ± 6i)/10
- x = (4 ± 3i)/5
x = (r ± si)/t
r = 4, s = 3, t = 5
3 1/3 would be the answer
Answer:
g(x) = 2x² + 1
Step-by-step explanation:
The parabola got thinner, so to show that, you put a 2 <u><em>before</em></u> x²<em> </em>to show that the graph was <em>dilated </em>(or thinned) by a factor of <em>2 </em>(Note: this number can also be <em>negative</em>, so if the dilation factor is negative, it's okay). Since the parabola shifts up by <em>1</em>, you then add + 1<em> </em><em><u>after</u></em> x² to show the positive upward shift.
Your full equation would look like this: g(x) = 2x² + 1
Dilation: this just means that every point on the parent function was double (or whatever the factor is) in the transformed function.
Answer:
<em>Two possible answers below</em>
Step-by-step explanation:
<u>Probability and Sets</u>
We are given two sets: Students that play basketball and students that play baseball.
It's given there are 29 students in certain Algebra 2 class, 10 of which don't play any of the mentioned sports.
This leaves only 29-10=19 players of either baseball, basketball, or both sports. If one student is randomly selected, then the propability that they play basketball or baseball is:

P = 0.66
Note: if we are to calculate the probability to choose one student who plays only one of the sports, then we proceed as follows:
We also know 7 students play basketball and 14 play baseball. Since 14+7 =21, the difference of 21-19=2 students corresponds to those who play both sports.
Thus, there 19-2=17 students who play only one of the sports. The probability is:

P = 0.59