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3 years ago

Evaluate N/6 + 2 when n=12

Mathematics

1 answer:

timurjin [86]3 years ago

5 0

Answer:

Step-by-step explanation:

n/6 + 2 If n = 12

12/6 + 2

2 + 2 = 4

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Is 4/3 and 8/6 a proportion

Alexus [3.1K]

Answer:

yes

Step-by-step explanation:

If you divide one into the other and the answer is 1 then they are of the same ratio.

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3 years ago

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tiny-mole [99]

Step-by-step explanation:

x= -7 y=0

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$y = - \frac{x}{3} - 7$

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2 years ago

The angle of the roof is 56 she built the doll house with a scale of 1:4 what is it measured

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3 years ago

Fill in the blank to make it a true statement: 50 ___ |-50|

Sergeeva-Olga [200]

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I don’t really have an explanation but that’s the answer

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2 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

3 years ago