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Nata [24]
3 years ago
11

Is ​(3​,9​) a solution of the system of linear​ equations?

Mathematics
2 answers:
Harrizon [31]3 years ago
7 0
The answer to that question is yea
sergeinik [125]3 years ago
4 0

Step-by-step explanation:

okay I'm not sure but dang you're beautiful

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Distance Formula D=√(x2-x1)² + (y2 - y₁) ² a. 8.149 b. 8.84 c. 9.438 d.12.369 ​
lakkis [162]

Answer:

d

Step-by-step explanation:

using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = (- 2, 4 ) and (x₂, y₂ ) = (10, 1 )

d = \sqrt{10-(-2))^2+(1-4)^2}

   = \sqrt{(10+2)^2+(-3)^2}

  = \sqrt{12^2+9}

  = \sqrt{144+9}

  = \sqrt{153}

  ≈ 12.369

5 0
2 years ago
Simplify 11^-4/11^5 <br> A 1/11^12<br> B 1/11^4<br> C 11^4<br> D 11^12
ad-work [718]

Answer:

a

Step-by-step explanation:

7 0
3 years ago
Given y=1/4x+2, i first isolate the constant. After doing so , i get the equation -1/4x+y=2.To remove the fraction, i multiply b
dexar [7]

Answer: this is wrong. The final answer should be x - 4y = 8

Step-by-step explanation:

y = 1/4x + 2

We'll first isolate the constant

-1/4x + y = 2

We remove the fraction by multiply through both sides of the equation

-4

x - 4y = 8

3 0
3 years ago
Solve for x: 2(x + 3)2 − 4 = 0
asambeis [7]

Answer:

Option D) x = −4.41, −1.59

Step-by-step explanation:

We are given the following expression in the question:

2(x + 3)^2 - 4 = 0

Solving the above expression, we get:

2(x + 3)^2 - 4 = 0\\2(x^2+9+6x)-4=0\\\text{Identity: }(a+b)^2 = a^2 + b^2 + 2ab\\2x^2+18+12x-4=0\\2x^2+12x+14=0\\\text{Using the quadratic formula:}\\ax^2 + bx +_ c = 0\\\\x = \displaystyle\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\text{Puting a = 2, b = 12, c = 14}\\\\x = \displaystyle\frac{-12\pm \sqrt{(12)^2-4(2)(14)}}{2(2)}\\\\x = \frac{-12 \pm 5.65}{4}\\\\x = \frac{-12 + 5.65}{4}, \frac{-12-5.65}{4} = -1.5875, -4.4125 \approx -1.59, -4.14

6 0
3 years ago
Read 2 more answers
Use the graph of the polynomial function to find the factored form of the
Anarel [89]

The factored form of the related polynomial is (x - 1)(x - 9)

<h3>How to determine the factored form of the related polynomial?</h3>

In this question, the given parameter is the attached graph

From the graph, we can see that the curve crosses the x-axis at two different points

These points are the zeros of the polynomial function.

From the graph, the points are

x = 1 and x = 9

Set these points to 0

x - 1 = 0 and x - 9 = 0

Multiply the above equations

(x - 1)(x - 9) = 0

Remove the equation

(x - 1)(x - 9)

Hence, the factored form of the related polynomial is (x - 1)(x - 9)

Read more about polynomial at:

brainly.com/question/4142886

#SPJ1

4 0
2 years ago
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