Answer:
B. 12
Step-by-step explanation:
✔️Find the value of x
The side lengths of two similar triangles are always proportional.
Given that ∆ABC ~ ∆LMN, therefore:

AB = 5
LM = 10
AC = x + 5
LN = 3x + 3
Plug in the values

Cross multiply

(distributive property)
Collect like terms
Divide both sides by 5
x = 7
✔️Find AC
AC = x + 5
Plug in the value of x
AC = 7 + 5
AC = 12
Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e









The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Because the polynomial has degree 2, we can assume that there are 2 solutions (roots), whether real or imaginary.
You can subtract 60 in order to put this in standard form
48x^2+44x-60 = 0
From there, just put a,b, and c into the quadratic formula and you're good to solve for your answers.
(-b+-sqrt(b^2-4ac))/2a
(-44+-sqrt(44^2-4(48)(-60)))/2(48)
Then solve.
There is probably a better way, but this should give you the two roots/solutions.
Answer:
C : -6
Step-by-step explanation:
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