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Luda [366]
3 years ago
12

Can you explain it and help me out please​

Mathematics
2 answers:
GREYUIT [131]3 years ago
8 0
The answer would be c on this
Anarel [89]3 years ago
6 0

Answer:

c.

Step-by-step explanation:

2x² - 4x - 3 = 0

x= \frac{-b+/-\sqrt{b^{2}-4ac} }{2a} \\\\x= \frac{-(-4)+/-\sqrt{(-4)^{2}-4*2*(-3)} }{2*2} \\\\x= \frac{4+/-\sqrt{16+24} }{4} \\\\x= \frac{4+/-\sqrt{40} }{4} = \frac{4+/-2\sqrt{10} }{4}=\frac{2+/-\sqrt{10} }{2}

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What is the answer to this equation in distributive property -4(2x-5)
Shalnov [3]

Answer:-4(2x-5)

Step-by-step explanation:

-4(2x-5)

-4(2x)+(-4)(-5)

-8x+20

-8/-4x+20/-4

-4(2x-5)

5 0
3 years ago
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A rectangular prism shaped fish tank is 14 in tall the perimeter of the base is 96 in the length of the base is 3 times the widt
Alla [95]

Using the given information find the length and width of the base:

Perimeter = 2L + 2W

L = 3W

Replace L in the first equation:

Perimeter = 2(3W) + 2w

96 = 2(3W) +2W

Simplify:

96 = 6W +2W

96 = 8w

Divide both sides by 8:

w = 96 / 8

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The width is 12 inches.

The length = 3 x 12 = 36 inches.

Volume = L x W X H

Volume = 36 x 12 x 14

Volume = 6,048 cubic inches.

5 0
3 years ago
What is the solution of StartFraction negative 8 Over 2 y minus 8 EndFraction = StartFraction 5 Over y + 4 EndFraction minus Sta
antiseptic1488 [7]

Answer:

  y = 6

Step-by-step explanation:

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6 0
3 years ago
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In the past decades there have been intensive antismoking campaigns sponsored by both federal and private agencies. In one study
DIA [1.3K]

Answer:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

Step-by-step explanation:

Information provided

X_{1}=1642 represent the number of smokers from the sample in 1995

X_{2}=1415 represent the number of smokers from the sample in 2010

n_{1}=4276 sample from 1995

n_{2}=3908 sample from 2010  

p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

z would represent the statistic    

p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

7 0
3 years ago
A random sample of 77 fields of corn has a mean yield of 26.226.2 bushels per acre and standard deviation of 2.322.32 bushels pe
PSYCHO15rus [73]

Answer:

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

Step-by-step explanation:

n = 77

mean u = 26,226.2  bushels per acre

standard deviation s = 2,322.32

let E = true mean

let A = test statistic

Find 95% Confidence Interval

so

let  A =  (u - E) *  (\sqrt{n}  / s)   be the test statistic

we want      P( average_l <  A  < average_u )  = 95%

look for  lower 2.5%  and the upper 97.5%  Because I think this is a 2-tail test

average_l =  -1.96  which corresponds to the 2.5%

average_u = 1.96

P(  -1.96  <  A  <  1.96)  =  95%

P(  -1.96  <  (u - E) *  (\sqrt{n}  / s)  <  1.96)  =  95%

Solve for the true mean E ok

E   <   u + 1.96* (s  / \sqrt{n})

from  -1.96  <  (u - E) *  (\sqrt{n}  / s)

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  1.96*( 2,322.32 / \sqrt{77} )

E < 26,226.2 +  518.7197348105429466

upper bound is 26,744.9197

or

u - 1.96* (s  / \sqrt{n})  < E

26,226.2 -  518.7197348105429466  < E

25,707.48026519  < E

lower bound is 25,707.48026519

Therefore the  95% confidence interval is (25,707.480 < E < 26,744.920)

7 0
3 years ago
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