Answer: 278.30 pounds (if the gasoline does not contain ethanol)
317.12 pounds (if the gasoline does contain ethanol)
Step-by-step explanation:
If the truck averages 12 miles per gallon, then in 170 miles it consumes:
170mi/12mi = 14.17 gallons.
We know that for one gallon consumed, the carbon dioxide emitted into the atmosphere is 19.64 pounds. (assuming it does not contain ethanol)
Then for 14.17 gallons consumed, we have a emission of:
14.17*19.64 pounds = 278.30 pounds
I the gasoline contains ethanlol, for a gallon the emiision is around 22.38 pounds.
In this case the total emission is:
14.17*22.38 pounds = 317.12 pounds
<span>rotated 90° about the origin
(x,y) = (-y, x)
so </span><span>(5, -2) is rotated 90° about the origin = (2, 5)
answer
</span><span>b.(2, 5)</span>
The area needed is at least 170.5 ft².
Let w = the width of the rectangular area.
Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is
(15.5 ft)*(w ft) ≥ 170.5 ft²
w ≥ 170.5/15.5
w ≥ 11 ft
Answer: w ≥ 11 ft
Given that <span>For
a certain model of car the distance
required to stop the vehicle if
it is traveling at
mi/h is given by the formula
![d=v+\frac{v^2}{20}, where [tex]d](https://tex.z-dn.net/?f=d%3Dv%2B%5Cfrac%7Bv%5E2%7D%7B20%7D%2C%20where%20%5Btex%5Dd%20)
is measured in feet.
If Kerry wants her stopping distance not to exceed 75
ft, then the range of speeds (in mi/h) can she travel is obtained as follows:
Therefore, the range of speed she can travel is
</span>
