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Butoxors [25]
3 years ago
11

I need answer please​

Mathematics
1 answer:
alexandr1967 [171]3 years ago
6 0

Answer: Angles 2 and 3 are vertical angles

Step-by-step explanation:

Vertical angles are angles that are not adjacent, and are made by the same 2 lines.

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What are the solutions to the following system of equations? Select the correct answer. y=x^2-4x+8 4x+y=12
lorasvet [3.4K]
Y=x^2-4x+8 and 4x+y=12 so y=12-4x, insert y in the quadratic to get
12-4x=x^2-4x+8
12=x^2+8
0=x^2-4=(x-2)(x+2)
So the solutions are x=2 and x=-2.
7 0
3 years ago
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An ellipse has a center at the origin, a vertex along the major axis at (10, 0), and a focus at (8, 0). Which equation represent
Alchen [17]
Check the picture below.  So the ellipse looks more or less like so.

since the major axis is over the x-axis, is a horizontal ellipse, notice the "a" component length and the value for "c".

\bf \textit{ellipse, horizontal major axis}
\\\\
\cfrac{(x- h)^2}{ a^2}+\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a,  k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2- b ^2}
\end{cases}\\\\
-------------------------------

\bf \begin{cases}
h=0\\
k=0\\
a=10\\
c=8
\end{cases}\implies 8=\sqrt{a^2-b^2}\implies 8^2=a^2-b^2\implies b^2=10^2-8^2
\\\\\\
b=\sqrt{100-64}\implies b=6
\\\\\\
\cfrac{(x-0)^2}{10^2}+\cfrac{(y-0)^2}{6^2}=1\implies \cfrac{x^2}{100}+\cfrac{y^2}{36}=1

3 0
4 years ago
Read 2 more answers
I need help with both of them please
kaheart [24]
5. it is A..............
3 0
3 years ago
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∠A and \angle B∠B are complementary angles. If m\angle A=(4x-28)^{\circ}∠A=(4x−28)
Igoryamba

Answer:

∠A = 26°

Step-by-step explanation:

Supplementary angles total 180°.

 ∠A +∠B = 180°

 (x -16)° +(3x +28)° = 180°

 4x° + 12° = 180°

 x° +3° = 45°

 x° = 42°

 ∠A = (x -16)° = 42° -16°

 ∠A = 26°

brainliest please?

5 0
4 years ago
"Find y". I got this wrong and want to understand why and how to do the problem. Can someone please help?
podryga [215]

Answer:

y=\frac{15\sqrt{3} }{4}

Step-by-step explanation:

Well what you have here are two right triangles within another right triangles created by an altitude. This results in 3 similar triangles (see attached for reference)

As a result , using the properties of similar triangles, and taking ratios of their sides of the medium triangle and the largest triangle, we can form the following relationship:

\frac{b}{z}=\frac{y}{x} = \frac{z}{a+b}  (we know that a+b = 15), hence the equation becomes:

\frac{b}{z}=\frac{y}{x} = \frac{z}{15}  ----------eq 1

If we consider the largest triangle, we will see that

cos 30° = z / 15

but from our special angles (see second attachment) we know that cos 30° = (√3)/2

hence

(√3)/2 = z / 15

z = (15√3) / 2 --------eq 2

from the same largest triangle, we will also see that

sin 30° = x / 15

similarly from our special angles, we know that sin 30° = 1/2

hence,

1/2 = x/15

x = 15/2 --------eq 3

now that we have values for x and z, we can neglect the first term of equation 1 and form an equality with x, y and z

\frac{y}{x} = \frac{z}{15}

y = x\frac{z}{15}  (substituting the values for x and z that we found above)

y = (15/2) · [ (15√3) / 2] / 15

y = (15√3) / 4

y=\frac{15\sqrt{3} }{4}

8 0
3 years ago
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