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Rom4ik [11]
2 years ago
8

Ms.Perkins predicted that 20% of the days in March would have temperatures below freezing. How many days does she predict will j

ave temperatures below freezing?​
Mathematics
1 answer:
lorasvet [3.4K]2 years ago
4 0

Answer:

Roughly 6.2 days will have below freezing according to Ms. Perkins

Step-by-step explanation:

20% of days in march Ms Perkins predicts will be below freezing.

March in the year 2019 has 31 days

20% is the same as .20

.20 * 31 = 6.2

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HELP PLEASE <br><br>must show work <br><br>I have the answer just need to show work​
Kazeer [188]

Answer:

Step-by-step explanation:

To solve these equations involving variables and exponents we need to follow these steps.

1) We need to find out the factor that is common in the equation.

2) After taking common, solve the equation. We can add or subtract only those values that have same bases.

1) 8+6x^4

here we can see, both numbers are divisible by 2, so taking 2 common

=2(8/2 + 6x^4/2)\\= 2(4 + 3x^4)

It cannot be further simplified because both number donot have same bases.

3.4n^9 + 12 n

We can take 4n common

=4n(4n^9/4n + 12 n/4n)\\=4n(n^8 + 3)

5. -12a -3

Here -3 cam be taken common

= -3(-12a/-3 -3/-3)

= -3(4a +1)

7. 12n^5 + 16n^3

here the smallest power of n is n^3 so, we can take n^3 common and both coefficients are divisible by 4 so taking 4n^3 common

4n^3( 3n^2 + 4)

9. 5k^2 - 40k+10

Here we cannot take k common, as k is not a multiple of 10. For taking common it should be divisible by each value in the equation. But each value s divisible by 5 so, taking 5 common

=5(k^2 - 8k + 2)

11.-60 + 60n^2 +50n^3

Here we cannot take n common, as n is not a multiple of -60. For taking common it should be divisible by each value in the equation. But each value s divisible by 10 so, taking 10 common

=10(-6 + 6n^2 +5n^3)

13. -36n^3 -12n-28

Here we cannot take n common, as n is not a multiple of 28. For taking common it should be divisible by each value in the equation. But each value s divisible by -4 so, taking -4 common

=-4(9n^3 + 3n +7)

15. 63n^3+81n+18

Here we cannot take n common, as n is not a multiple of 18. For taking common it should be divisible by each value in the equation. But each value s divisible by 9 so, taking 9 common

=9(7n^3 + 9n + 2)

17. -24a^2b^2 + 36ab-60a

=6a(-4ab^2+6b-10)

3 0
3 years ago
The heaviest dinosaur is estimated to have welghed 2.8 x 10^5 pounds. The average car weighs about 4 x 10^3 pounds.
34kurt

Answer:

  70

Step-by-step explanation:

Apparently, you want the ratio of the weights:

  (dino weight)/(car weight) = (2.8×10^5)/(4×10^3)

  = (2.8/4)×10^(5-3) = 0.7×10^2 = 0.7×100

  = 70

The heaviest dinosaur weighed about 70 times the weight of an average car.

_____

Your calculator can do arithmetic in scientific notation. So can any spreadsheet.

The applicable rule of exponents is ...

  (10^a)/(10^b) = 10^(a-b)

4 0
2 years ago
Pleasee help me I just wanna go to sleep already :c
Lunna [17]

Answer: 17 is A and 18 is B

Used a calculator to add them all up! Get some sleep hope this helps.

17) 2(3x8)+2(3x6)+2(6x8) = 180

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8 0
2 years ago
a certain state the license plate has two digits, then two letters, and then two digits. How many different license plates are p
xxTIMURxx [149]

Step-by-step explanation:

Choosing 4 digits out of 10 = 10C4 = 210.

Arranging the 4 digits in 4 places = 4!

Total number of ways to arrange digits

= 210 * 4! = 5040.

Choosing 2 letters out of 26 = 26C2 = 325

Arranging the 2 letters in 2 places = 2!

Total number of ways to arrange letters

= 325 * 2! = 650.

Total number of possible license plates

= 5040 * 650 = 3,276,000.

7 0
2 years ago
Read 2 more answers
Solve for x in the equation x^2 - 8x + 40 = 0​
laiz [17]

Answer:

Conclusion : Trinomial can not be factored

Step-by-step explanation:

5 0
2 years ago
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