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2 years ago

One of the legs of a right triangle measures 8 cm and the other leg measures 12 cm.

Mathematics

1 answer:

Brut [27]2 years ago

8 0

Answer:

14.4 cm

Step-by-step explanation:

We solve the above question using Pythagoras Theorem

The formula is given as:

c ² = a² + b ²

Where:

c = Hypotenuse

a = 8cm

b = 12 cm

Hence,

c² = 8² + 12²

c² = 64 + 144

c² = 208

We square root both sides

c = √(208)

c = 14.422205102 cm

Approximately to the nearest tenth = 14.4 cm

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3 years ago

Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 4 and 3−

Neko [114]

Answer:

$P(x) = x^3 - 10x^2+ 34x-40$

Step-by-step explanation:

Given

$p =1$ -- Leading coefficient

$Zeros: 4\ and\ 3 - i$

Required

Determine the polynomial

Represent the zeros with a and b

Such that

$a = 4$

$b = 3 - i$

The polynomial is:

$P(x) = p * (x - a) * (x - b)$

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However, to solve further: We need to symmetrise over 3-i and its conjugate

$P(x) = 1 * (x - 4) * (x - (3 - i))* (x - (3 + i))$

$P(x) = (x - 4) * (x - (3 - i))* (x - (3 + i))\\\\$

To define a suitable function, the expression becomes

$P(x) = (x - 4) * ((x - 3)^2+1)$

$P(x) = (x - 4) * ((x - 3)(x - 3)+1)$

$P(x) = (x - 4) * (x^2 - 6x + 9+1)$

$P(x) = (x - 4) * (x^2 - 6x +10)$

Open bracket

$P(x) = x^3 - 6x^2 +10x - 4x^2 + 24x-40$

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2 years ago

Math help what is the answer will give brainliest.

artcher [175]

The two equations are
$x + y = 7$
and
$4x + 2.5y = 22$
the first equation can be solved for x to be
$x = 7 - y$
next you can substitute x in the second equation
$4(7 - y) + 2.5y = 22$
Distribute 4 to everything in the parentheses
$28 - 4y + 2.5y = 22$
combine like terms:
$28 - 1.5y = 22$
subtract 28 from both sides of the equation
$- 1.5y = - 6$
divide both sides by -1.5
$y = 4$
plug this in to the original equation of x+y=7
$x + 4 = 7$
subtract 4 from both sides.
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Final Answer: they bought 3 adult tickets and 4 student tickets

Hope this helps!

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3 years ago

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Gemiola [76]

Answer:

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Step-by-step explanation:

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