I think the answer would be 89
Answer:
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Step-by-step explanation:
Given that :
Mean = 265
standard deviation = 14
The formula for calculating the z score is 
x = μ + σz
At middle of 50% i.e 0.50
The critical value for 
From standard normal table
+ 0.67 or -0.67
So; when z = -0.67
x = μ + σz
x = 265 + 14(-0.67)
x = 265 -9.38
x = 255.62
when z = +0.67
x = μ + σz
x = 265 + 14 (0.67)
x = 265 + 9.38
x = 274.38
the middle 50% of most lengths of pregnancies ranges between 255.62 days and 274.38 days
Answer:
what is the question?
Step-by-step explanation:
Using the table, we will see that the function is:
t(l) = 3*l
<h3>
How to write the function?</h3>
Here we only have a table to work with, so we need to use that.
In the table, we can see the pairs:
- t(1) = 3
- t(2) = 6
- t(3) = 9
- t(4) = 12
So, in each new level, we just add 3 more toothpicks. Even more, we can see that the number of toothpicks is 3 times the value of l (the level) for all the cases in the table. So this is a linear function.
From that we can conclude that the function will be:
t(l) = 3*l
If you want to learn more about linear functions, you can read:
brainly.com/question/4025726
So assuming that youmeans there were 35 MORE rose plants than sunflower seeds, then
Rose:Sunflower =8:3
rose=sunflower+35
therefor
8 units=rose
3 units=sunflowers
rose-35=sunflower
8unit-35=3unit
5unit-35=0
5unit=35
therefor
35=5unit
divide by 5
7=1unit
so 8 units of roses
7 times 8=56
3 units of sunflowers
3 times 7=21
rose=56
sunflower=21
