The sphere and the cylinder have the same heightbecause of this the height of the cylinder is equal to the diameter of the spherethe diameter of the sphere is 2*7=14 cm, so the height of the cylinder is also 14 cmthe radius of the cylinder is 7 cmV=∏*r^2*hV=3.14159*7^2*14V=3.14159*49*14V=3.14159*686V=2155.13074 cubic cm, or...V=(22/7)(7^2)(14) (22/7 is an approximation for pi)V=(22/7)(49)(14)V=(22)(7)(14)V=(22)(98)V=2156 cubic cm
Answer:
6
Step-by-step explanation:
Write the prime factorizations:
24 = 2³ × 3
30 = 2 × 3 × 5
The greatest common factor is the product of the common factors at their lowest exponents.
GCF = 2 × 3
GCF = 6
115:55 bc if you divide them both you fat the same answer which is 2
Answer:
(1) .20 (2) .40 (3) .12 (4) Less than
Step-by-step explanation:
You have to look at the table. There are 5 columns with 10 rows. 5x10=50
Then simply count the boxes that have the correct number of currency for instance, if they are asking for EXACTLY 1 dime then you rule out the ones that have 2 or 3 dimes and only the count the ones that have a single dime. So you count PDN but you would not count PDD. There are 20 boxes that have a single dime in them. 20 out of the 50 boxes. 20/50=.40 (answer 2)
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is .
20
The estimated probability that exactly one of the three coins Avery randomly picked is a dime is .
40
The estimated probability that all three coins Avery randomly picked are pennies is .
12
The answer to #1 is .20 or 20% and the answer to #2 is .40 or 40%. 20% is less than 40% so...
The estimated probability that exactly two of the three coins Avery randomly picked are nickels is LESS THAN the estimated probability that exactly one of the three coins Avery randomly picked is a dime.
He passed out 91 objects. 13 x 4 = 52 + 39 = 3 x 13
