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3 years ago

3x-2y=-1. Y=-x+3. Is (1,2) a solution do the system?

Mathematics

2 answers:

andrew-mc [135]3 years ago

8 0

Answer:

Yes

Step-by-step explanation:

To figure out if (1,2) is a solution to the system, we can plug the values in and see if it is true.

3x-2y=-1

3(1)-2(2)=-1

3-4=-1

-1=-1

It is true for this equation. Now let's check the next one.

y=-x+3

2=-(1)+3

2=2

Since both equations are true when we plug the values in, (1,2) is a solution to the system.

Stells [14]3 years ago

3 0

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Otherwise, you can derive the same result. Let $\theta=\sin^{-1}\dfrac12$ , so that $\sin\theta=\dfrac12$ . $\sin^{-1}$ is bounded, so we know $-\dfrac\pi2\le\theta\le\dfrac\pi2$ . For these values of $\theta$ , we always have $\cos\theta\ge0$ .

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Then

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Mazyrski [523]

Answer:

If, a = 2 and b = 3

It's not equivalent.

<h3>Diego</h3><h3> $4a + 9b = 7a + 5b - 3a + 4b \\ 4(2) + 9(3) = 7(2) + 5(3) - 3(2) + 4(3) \\ 8 + 27 = 14 + 15 - 6 + 12 \\ 35 = 35 \\$ </h3>

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