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3 years ago

12

Calcular x en: los datos q faltan

1 answer:

Taya2010 [7]3 years ago

4 0

Answer:

x = 13

Step-by-step explanation:

No se exactamente como decir esto porque yo ayudo la majoria de los usuario en ingles pero hay que usar un método para describir a x

Un método que se llama Pythagorean theorem

Pythagorean theorem: a^2 + b^2 = c^2 donde a^2 = 5 b^2 = 12 y c^2 = x

Entonces…

5^2 + 12^2 = c^2

Nota: podemos ver que esto esta bien porque el sum de los dos lados suma el mas largo.

Ahora

25 + 144 = c^2

c^2 = 169

Pero eso no puede ser la respuesta porque no tiene sentido a que x sea un lado que mide 169 entonces tenemos que usar sqrt rt

sqrt rt de 169 = 13

x = 13

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VikaD [51]

Answer:

The Answer is Gross income. Hope this helps!

Step-by-step explanation:

3 0

3 years ago

Someone help and please make sure it’s right :)

pashok25 [27]

Answer:

9

Step-by-step explanation:

$11x + 1 + 7x + 17 = 180 \: \: \: \: 18x + 18 = 180 \: \: \: \: \: \: \: 18x = 180 - 18 \: \: \: \: \: \: \: \:18x = 162 \: \: \: \: \: \: \: \: \: \: 162 \div 18 = 9$

4 0

2 years ago

Lily has two times as much money invested in 8% stocks as she has in bonds paying 6%. How much she has invested in stocks if her

EleoNora [17]

Answer:

Final answer is $4440.

Step-by-step explanation:

Let amount of money invested in 8% stock = x

Let amount of money invested in 6% stock = y

then total money invested $325.6 gives equation

8% of x + 6% of y = 325.6

0.08x + 0.06y = 325.6

8x + 6y = 32560...(i)

other equation will be x=2y...(ii)

plug (ii) into (i)

8x + 6y = 32560

8(2y) + 6y = 32560

16y+ 6y = 32560

22y = 32560

$y=\frac{32560}{22}$

y=1480

plug y=1480 into (ii)

x=2y=2(1480)=2960

Then total money invested in stocks = x+y= 1480+2960=4440

Hence final answer is $4440.

5 0

2 years ago

Enteroliths are calcifications that form in the gut of a horse. The stones can cause considerable morbidity and mortality. A stu

juin [17]

Answer:

A. mean=14.29

median=16

B. IQR=10

C. option 3

D. 5.91

Step-by-step explanation:

mean=sum of values/number of values=10+20+4+13+21+16+16/7=14.29

median is achieved by arranging data in increasing order and then calculating the middle value

4 10 13 16 16 20 21

The mid value is 16 so the median=16

IQR=interquartile range=3rd quartile-1st quartile=Q3-Q1=20-10=10

As n/4=7/4 is not an integer so

Q1=(n/4+1)value=(7/4+1)=2.75=2nd value=10

Q3=(3n/4+1)value=6.25=6th value=20

Standard deviation=s=sqrt(∑(x-xbar)²/n-1)=sqrt(209.43/6)=5.91

7 0

2 years ago

Applying properties of Exponents In Exercise, use the properties of exponents to simplify the expression.

Nastasia [14]

Answer:

(a) $4^7$

(b) $7^6$

(c) $\dfrac{1}{16}$

(d) $3^{4}$

Step-by-step explanation:

We need to simplify the given expressions.

(a)

Consider the given expression is

$(4^5)(4^2)$

Using the property of exponent, we get

$=4^{5+2}$ $[\because a^ma^n=a^{m+n}]$

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(b)

Consider the given expression is

$(7^2)^3$

Using the property of exponent, we get

$=7^{2\times 3}$ $[\because (a^m)^n=a^{mn}]$

$=7^6$

(c)

Consider the given expression is

$2^{-4}$

Using the property of exponent, we get

$=\dfrac{1}{2^{4}}$ $[\because a^{-n}=\dfrac{1}{a^n}]$

$=\dfrac{1}{16}$

(d)

Consider the given expression is

$\dfrac{3^8}{3^4}$

Using the property of exponent, we get

$=3^{8-4}$ $[\because \dfrac{a^m}{a^n}=a^{m-n}]$

$=3^{4}$

6 0

3 years ago