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4 years ago

PLZ HELP IM TIMED!!!

Mathematics

2 answers:

gavmur [86]4 years ago

8 0

Answer:A

Step-by-step explanation:

SVEN [57.7K]4 years ago

6 0

Answer:

It should be A

Step-by-step explanation:

multiply the - by 7/8 to get -7/8

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If the polynomial x^5 − 10^5 can be split as the product of the polynomials

AfilCa [17]

Hello,

x^5-10^5=(x-10)(x^4+10x^3+100x^2+1000x+10000)
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7 0

3 years ago

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vichka [17]

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6 0

3 years ago

Solve the inequality 4t^2 ≤ 9t-2 please show steps and interval notation. thank you!

FromTheMoon [43]

Answer: $t\in [\dfrac{1}{4},2]$

Step-by-step explanation:

Given

Inequality is $4t^2\leq9t-2$

Taking variables one side

$\Rightarrow 4t^2-9t+2\leq0\\\Rightarrow 4t^2-8t-t+2\leq0\\\Rightarrow 4t(t-2)-1(t-2)\leq0\\\Rightarrow (4t-1)(t-2)\leq0$

Using wavy curve method

$t\in [\dfrac{1}{4},2]$

3 0

3 years ago

Scarlett and Alyssa work at a dry cleaners ironing shirts. Scarlett can iron 15 shirts per hour, and Alyssa can iron 35 shirts p

hodyreva [135]

Answer:

25x + 35(2x) = 380

25x + 70x = 380

95x = 380 so

x = 4

then i think that mean it might be 8 then im not completly sure

6 0

3 years ago

(x/x+3)-(8/x+2)=(-13x-6)/(x^2+5x+6)

Fed [463]

Answer:

x = -9

x = 2

Step-by-step explanation:

Given:

$\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{x^2+5x+6}$

First, note that

$x^2+5x+6=x^2+2x+3x+6=x(x+2)+3(x+2)=(x+2)(x+3)$

Since $x+2$ and $x+3$ stay in the denominator, then

$x\neq -2\ \text{and}\ x\neq -3$

Now add two fractions which stay in the left part. The common denominator is $(x+2)(x+3),$ so multiply the numerator of the first fraction by $(x+2)$ and the numerator of the second fraction by $(x+3)$ and subtract them in the numerator:

$\dfrac{x}{x+3}-\dfrac{8}{x+2}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\\dfrac{x(x+2)-8(x+3)}{(x+2)(x+3)}=\dfrac{-13x-6}{(x+2)(x+3)}\\ \\x(x+2)-8(x+3)=-13x-6\\ \\x^2+2x-8x-24=-13x-6\\ \\x^2+2x-8x+13x-24+6=0\\ \\x^2+7x-18=0\\ \\x^2+9x-2x-18=0\\ \\x(x+9)-2(x+9)=0\\ \\(x+9)(x-2)=0\\ \\x+9=0\ \text{or}\ x-2=0\\ \\x=-9\ \text{or}\ x=2$

3 0

3 years ago