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Leviafan [203]
3 years ago
7

I WILL MARK BRAINLIEST IF CORRECT

Mathematics
2 answers:
Pachacha [2.7K]3 years ago
5 0

Answer:

The answer is D 55.7 my friend

zaharov [31]3 years ago
3 0
I’m guessing the answer would be C
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ABC ~ ADE AC = 4, AE = 7, AD = 10, what is the length of AB? 1 3/7 2 1/2 5 5/7 17 1/2
Butoxors [25]

If the polygon or the figures are similar then it is known that the ratios of their corresponding sides and angles are proportional. In this item we can derive an equation that is,

<span>                        AC/AE = AD/AB</span>

Substituting the known values,

<span>                      4/7 = 10/AB</span>

<span>AB from the equation is equal to 70/4 or equal to 17 ½. </span>

3 0
4 years ago
Read 2 more answers
The length of a rectangle is 6 meters more than its width. If the area of the rectangle is 135 square meters, find its dimension
solniwko [45]
We have the formula for the area of a triangle equal to A=l*w, where stands for the area, l for the length and w for the width. Given in the problem are the following:
A=135 m
l=6+w
w=w
Solving for the value of w, we have:
A=(w+6)*w
135=w²+6w
w=9 meters
Therefore, the length of the rectangle is 15 meters.
8 0
3 years ago
The coordinates of the endpoints of AB and CD are A(2,
Ratling [72]

Answer:

Option 1: CD is a perpendicular bisector of AB

Step-by-step explanation:

Let us find out the slopes of various line segments and the Distances and then we will draw the conclusions accordingly.

Formula to find slope

m= \frac{y_2-y_1}{x_2-x_1}

Formula to Find Distance between two points

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

mAB ( represents , Slope of AB )

1. mAC= \frac{3-2}{2-5}=\frac{1}{-3}=-\frac{1}{3}

2. mBC=\frac{2-1}{5-8}=\frac{1}{-3}=-\frac{1}{3}

3. mCD=\frac{5-2}{6-5}=\frac{3}{1}=3

4. AC=\sqrt{(3-2)^2+(2-5)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

5. BC=\sqrt{(2-1)^2+(5-8)^2} =\sqrt{(1)^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}

mAC = mBC  , and C is common point , hence these three are collinear points  making a straight line whole slope is -\frac{1}{3}

mAB=-\frac{1}{3}

mCD=3

mAB \times mCD = -\frac{1}{3} \times 3 = -1

Hence CD ⊥ AB

Also

From Point 4 and point 5 above , we see that

AC = CB

Hence CD bisect AB at C, also CD ⊥ AB

There fore

CD is a perpendicular bisector of AB

Therefor option 1 is true

4 0
3 years ago
) Which statements about -3 and -7 are true? Choose ALL the correct answers.
trasher [3.6K]

Answer: -3 is greater than -7 and the absolute value of -3 is less than the absolute value of -7.

Step-by-step explanation:

For NEGATIVE numbers, the closer the value is to 0, the greater it is. -3 is closer to 0 than -7 is, so -3 is greater than -7. For POSITIVE numbers, the further away the number is from 0, the greater it is. The absolute value of -3 is 3 and the absolute value of -7 is 7, and 7 is farther away from 0 than 3 is. So, the absolute value of -3 is less than the absolute value of -7. Hope this helps!

6 0
3 years ago
Evacuate 9-b when b-8
MakcuM [25]

9-b when b=8

9 -8 =1


9-b when b=-8

9 - (-8)

9+8

17


I'm  not sure whether you meant b=8 or b=-8

4 0
3 years ago
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