So y=mx+b
m=slope
y=-3x+b
subsitutue 1 for x and 4 for y
4=-3(1)+b
4=-3+b
add 3 to both sides
7=b
the equaiton is y=-3x+7
Answer:
<em><u>x=-6, y=-2</u></em>, (As a point) (-6, -2).....The point form is not necessary unless you want to solve the system (of equations) by graphing.
Step-by-step explanation:
By substitution:
x-y=-4 By adding y on both sides,
x=y-4
Now you can substitute x for the expression (y-4)
Plug the (y-4) as x in the other equation.
So -2x+3y=6 becomes
-2(y-4)+3y=6
Now solve:
-2(y-4)+3y=6 distributes out to be
-2y+8+3y=6 Now combining like terms
y+8=6 Subtract 8 on both sides to isolate the variable
<u><em>y=-2</em></u>
Now plug the value -2 in where the y is in any equation (preferably the easier/less complicated one) and solve for x.
So x-y=-4 becomes
x-(-2)=-4
=x+2=-4
=<u><em>x=-6</em></u>
If <em>X</em> is uniformly distributed on the interval (0, 12), then its PDF is
or simply
and the zero-elsewhere case is assumed.
Whether you include 0 and 12 in the domain is irrelevant, since the probability that <em>X</em> = 0 or <em>X</em> = 12 are both zero.
C= (-d/a) +b Hope this helps
