Answer:
5
Step-by-step explanation:
5*20=100
If the whole diameter of sphere is 6 inch(means radius is 3 inch) & thickness of material is 1 inch, so the radius of the hollow part should be 2 inch (3-1=2)
The total volume of the ball will be;
= Total volume - Volume of hollow part
= 4/3πr³ - 4/3πr³
= 4/3 × 3.14 × (3)³ - 4/3×3.14×(2)³
= 4 × 3.14 × 9 - 4/3 × 3.14 × 8
= 113.04 - 33.52
= 79.52
If the density of the material is 3.25 g/in3, then the density of 79.52 inch³ should be;
= 79.52 × 3.25
= 258.44 g
Now, if there are 8 spheres in one box, the weight if box will be;
= 258.44 × 8
= 2,067.52 g
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Ahh! Finally done with this, if you have any doubt just do ask me :)
Answer:
a)The component form is

b)The magnitude is √65
c) <2,14>
Step-by-step explanation:
Recall that:

We substitute the position vectors to get:

We subtract the corresponding components to obtain:

This gives:

This simplifies to:

The magnitude of a vector in the component form:

is

This means:

This simplifies to:


c) We have the vectors u = <4, 8>, v = <-2, 6>.
We want to find:
u+v
This implies that:
u+v=<4,8>+<-2,6>
We add the corresponding components to get;
u+v=<4+-2,8+6>
This simplifies to:
u+v=<2,14>
Answer:
2y = 3x + 21
y = 1.5x + 10.5
plug in, in the second equation
- 4x + (1.5x + 10.5) = 23
-4x + 1.5x + 10.5 = 23
-2.5x + 10.5 = 23
-2.5x = 12.5
x = 12.5/-2.5 = -5
y = 1.5 (-5) + 10.5 = 3
x = -5
y = 3