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3 years ago

Which is steeper: a line with a slope of 2/5 or a line of 5/2? How do you know? Explain.

1 answer:

3 0

5/2 because 5/2 is greater than 1, an improper fraction that does not take a piece of 1 but rather considers whole numbers as that origin

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Find the expected value of the winnings

adelina 88 [10]

Multiply each payout by the corresponding probability and take the total:

E[X] = 0×0.5 + 5×0.2 + 8×0.15 + 10×0.1 + 15×0.05 = 3.95

3 0

3 years ago

What is the circumference and area of a circle that has a radius of 12 ft? What would the arc length and area of the sector be i

Effectus [21]

Answer:

hi .......

Step-by-step explanation:

4 0

3 years ago

A bike shop rents each of its mountain bikes for a one time $4.00 insurance charge plus $2.50 per hour create an equation that r

egoroff_w [7]

Answer:

$y=2.50x+4.00$

Step-by-step explanation:

Let

x -----> the number of hours

y ----> the total cost to rent a bike in dollars

we know that

The equation of the line in slope intercept form is equal to

$y=mx+b$

where

m is the slope or the unit rate of the linear equation

b is the y-intercept or the initial value

In this problem we have

The unit rate or slope is equal to

$m=\$2.50\ per\ hour$

The y-intercept (value of y when the value of x is equal to zero) is equal to

$b=\$4.00$ ----> (fee charge)

substitute the values

$y=2.50x+4.00$

5 0

3 years ago

0.135 written as a fraction is _____. 5/37 27/100 27/200

sergij07 [2.7K]

First it would be 135/1000. Then you'd have to simplify.

Simplified, it would be 27/200.

4 0

3 years ago

Read 2 more answers

Joe began to increase the speed of his car at 2:00 P.M. Since that time,the speed of Joes car has been steadily increasing by 1

Olegator [25]

Answer:

7 mins

Step-by-step explanation:

Current speed of Joes Car = 65.5 mph

We have to find the time interval for which the car exceeded the speed limit of 55 mph.

While, we are given that the speed of the car was constantly increasing, hence the speed over all increased from the limit of 55 mph = 65.50-55.00 = 10.50 mph

We are also given that Joes car was increasing speed at a constant rate of 1.50 mph for every passing minute. Hence

1.50 mph is increased in 1 minute

1 mph will be increase in $\frac{1}{1.5}$ minutes

Hence

10.50 mph will be increased in $\frac{1}{1.5} \times 10.50$ minutes

$= \frac{10.5}{1.5}$

$=7$

Hence joes car was exceeding the limit of 55 mph for 7 minutes.

8 0

2 years ago