Answer:
P = 70 mi A = 210 mi^2
Step-by-step explanation:
Sides:
a = 29 m
b = 20 m
c = 21 m
Angles:
A = 90 °
B = 43.6028 °
C = 46.3972 °
Other:
P = 70 m
s = 35 m
K = 210 mi^2
r = 6 m
R = 14.5 m
Agenda:
A = angle A
B = angle B
C = angle C
a = side a
b = side b
c = side c
P = perimeter
s = semi-perimeter
K = area
r = radius of inscribed circle
R = radius of circumscribed circle
SSS is Side, Side, Side
Heron’s formula says that if a triangle ABC has sides of lengths a, b, and c opposite the respective angles, and you let the semiperimeter, s, represent half of the triangle’s perimeter, then the area of the triangle is
Is x=1/3 a possible answer? It would be if in fraction form.
or -31.
Hey!
Hope this helps...
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54 * (2/3) = 36 students were on the bus.
54 - 36 = 18 chaperones were on the bus.
Answer:c
Step-by-step explanation:none of these are good answers as they can all exist in flat Euclidean space. The best answer is c because a great circle exists in spherical (non-flat) geometry . However it’s not really correct to say you could never describe a great circle in Euclidean space and whoever wrote this question (not you, the original author of the question) deserves to bite their tongue on their dinner tonight
Answer:
x=1,y=-2
Step-by-step explanation:
