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Elena-2011 [213]
3 years ago
10

F(1) = 3, f(n) = [f(n-1)]?

Mathematics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

No, they are not equal.

Step-by-step explanation:

f(n) = f(n-1)

Let's say, n = 3. Let's put that in the equation:

f(3) = f(3-1)

f(3) = f(2)

Are they the same? Apparently, no. So, these two functions are not equal.

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Answer:

y = (1/4)x² - (5/4)x + 1

Step-by-step explanation:

The x-intercepts of the quadratic equation are simply it's roots.

Thus, we have;

(x + 1) = 0 and (x - 4) = 0

Now, formula for quadratic equation is;

y = ax² + bx + c

Where c is the y intercept.

At y-intercept: (0,1), we have;

At (-1,0), thus;

0 = a(1²) + b(1) + 1

a + b = -1 - - - (1)

At (4,0), thus;

0 = a(4²) + b(4) + 1

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Divide both sides by 4 to get;

4a + b = -1/4 - - - (2)

From eq 1, b = -1 - a

Thus;

4a + (-1 - a) = -1/4

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3a = 3/4

a = 1/4

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b = -5/4

Thus;

y = (1/4)x² - (5/4)x + 1

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