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atroni [7]
2 years ago
7

What is the length of Line segment A C? Round to the nearest tenth. 3.0 cm. 9.8 cm. 10.5 cm. 12.8 cm.

Mathematics
2 answers:
12345 [234]2 years ago
6 0

Answer:

10.5

Step-by-step explanation:

Simora [160]2 years ago
5 0

Answer:

10.5 cm

Step-by-step explanation:

A line segment is defined as a part of a line. It is a straight line having two end points. The only difference between a line and line segment is that a line is continuous with indefinite length whereas a line segment has a definite length to it between the two points.

In the figure, the length of the line segment is 10.5 cm (rounded to the nearest tenth).

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Given: 315/1575. Write the prime fractorization of the numerator and the denominator, then write the fraction in lowest terms.
Ne4ueva [31]
The prime factorization of the numerator, 315, is 5 x 3 x 3 x 7. That of the denominator, 1575 is 5 x 5 x 3 x 3 x 7. To convert the fraction to its lowest form, cancel all the factors that appear to both the numerator and denominator. We will be left with 1/5. 
3 0
3 years ago
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0
3 years ago
A boat traveled 27 miles in 2 hours. At this rate, how many miles will the boat travel in
Art [367]
6.75 miles per half hour !!!!!!!
7 0
3 years ago
Read 2 more answers
AS ALWAYS, DUE TODAY! Pls and thanks. NOTE- Legit answers only! Legit answers= Brainliest, 5.0 stars, and a Thanks.
Vesna [10]

Answer:

x=105 and y=190

Step-by-step explanation:

4x+1y=610, and x+y=295 ; x= 105 and y=190

8 0
3 years ago
Read 2 more answers
Please help iam lost
Goryan [66]

Answer:

x = 4.

Step-by-step explanation:

I am assuming that you want to find the values of x and that WXYZ is a parallelogram.

In a parallelogram opposite sides are equal, therefore:

11x + 1 = 19x - 31

1 + 31 = 19x - 11x

32 = 8x

x = 32/8 = 4.

6 0
3 years ago
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