Note:xy means x times y and x(y) means the same thing
so first we get rid of square root then make the equation equal to zero becaues if xy=0 then x or/and y=0
squareroot(y-1)+3=y
isolate the squareroot subtrac 3 from boht sides
squareroot(y-1)=y-3
square both sides (since they are equal, you should be able to square both sides and still make it true)
(squareroot(y-1))^2=(y-3)^2 (y-1)=(y-3)(y-3) y-1=y^2-6y+9 subtrac y from both sides -1=y^2-7y+9 add 1 to both sides 0=y^2-7y+10 find what two number multiply to make 10 and add to get -7 the answer is -2 and -5
0=(y-5)(y-2) therfore y-5=0 and/or y-2=0
therefor y=5 or/and 2 might work let's try out 2 square root(2-1)+3=2 square root(1)+3=2 1+3=2 false so 2 doesn't work
