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3 years ago

The statement below describes a situation in which opposite quantities combine to make zero:

Mathematics

2 answers:

topjm [15]3 years ago

6 0

The answer is false.

77julia77 [94]3 years ago

3 0

The answer is false. if the quantities combine to make zero

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Whats three billion plus five trillion lol

Ira Lisetskai [31]

Answer:

5,003,000,000,000

Step-by-step explanation:

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3 years ago

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Drag numbers to use a negative factor to factor the expression -59 + 15h - 25. Numbers may be used once, more than once, or not

koban [17]

Answer:

$-5(g - 3h + 5)$

Step-by-step explanation:

Given

$-5g + 15h - 25$

Required

Factor using a negative factor

Express each term as a factor of -5

$-5*g - 5*-3h - 5 * 5$

Factor out -5

$-5(g - 3h + 5)$

Hence:

The factored form of $-5g + 15h - 25$ is $-5(g - 3h + 5)$

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3 years ago

What is the simplified form of (5x^3 + 2)(5x^3 -2)

lapo4ka [179]

Simplify the expression.

25x6−4

plz mark me as brainliest :)

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3 years ago

To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI

nadya68 [22]

Part 1) To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

$\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}$

in this problem we have

$\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})$

therefore

the answer Part 1) is

Law of Sines

Part 2) To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

$g^{2}=h^{2}+i^{2}-2*h*i*cos\ G$

In this problem we have

g=HI

G=angle Beta

substitute

$HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta$

$HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}$

therefore

the answer Part 2) is

Law of Cosines

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2 years ago

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Solve 0 Divided by 0

galina1969 [7]

It would come out as an error because you cant divide nothing by nothing. There is nothing there to divide

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3 years ago

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