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3 years ago

What property of operations can be used to justify that the two expressions in this equation are equivalent? 6x^2 +4x=4x + 6x^2

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

8 0

Answer:

Commutative

Step-by-step explanation:

There are four basic property of operations to solve an algebraic expressions. They are associative, commutative, distributive and identity.

The expression given is : $6x^2 + 4x=4x+6x^2$

So the given algebraic expression is a commutative property of operations. The commutative property states that when any two numbers are added in an expression the sum of the numbers are the same regardless of the order of the numbers that are added.

Thus the sum of the above expression will be same in which ever order the numbers are added.

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What is the slope intercept form of the equation Y -7 equals -5 / 2 (x + 4 )

Sindrei [870]

Answer:

y=-5/7(x+4)+7

Step-by-step explanation:

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3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided.

shutvik [7]

Answer:

Step-by-step explanation:

we are given

(A)

(f×g)(x)=f(x)*g(x)

now, we can plug it

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(B)

Domain:

Firstly, we will find domain of f(x) , g(x) and (fxg)(x)

and then we can find common domain

Domain of f(x):

we know that f(x) is undefined at x=0

so, domain will be

∪

Domain of g(x):

Since, it is polynomial

so, it is defined for all real values of x

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∪..............Answer

Range:

Firstly, we will find range of f(x) , g(x) and (fxg)(x)

and then we can find common range

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we know that range is all possible values of y for which x is defined

since, horizontal asymptote will be at y=0

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∪

Range of g(x):

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6 0

3 years ago

What is the distance between point C and point D?

e-lub [12.9K]

Answer:

B. 13 units

Step-by-step explanation:

let

(x1 , y1) = (-4 , -6)

(x2 , y2) = (1 , 6)

distance between CD = root (x2 - x1)^3 + (y2 - y1)

= root {1 - ( -4)}^2 + {6 - ( -6)}^2

= root {1 +4}^2 + {6+6}^2

= root 5^2 + 12^2

= root 25 + 144

= root 169

= 13 units ans

6 0

3 years ago

Read 2 more answers

How to subrtact a negative from a negative?

Kamila [148]

Here, this website explains it perfectly

Step-by-step explanation:

https://www.k5learning.com/blog/subtracting-positive-and-negative-numbers

8 0

3 years ago

Read 2 more answers

Expand using the properties and rules for logarithms

malfutka [58]

Consider expression $\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).$

1. Use property

$\log_a\dfrac{b}{c}=\log_ab-\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.$

2. Use property

$\log_abc=\log_ab+\log_ac.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.$

3. Use property

$\log_ab^k=k\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.$

4. Use property

$\log_{a^k}b=\dfrac{1}{k}\log_ab.$

Then

$\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.$

Answer: correct option is B.

7 0

4 years ago