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3 years ago

What property of operations can be used to justify that the two expressions in this equation are equivalent? 6x^2 +4x=4x + 6x^2

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

8 0

Answer:

Commutative

Step-by-step explanation:

There are four basic property of operations to solve an algebraic expressions. They are associative, commutative, distributive and identity.

The expression given is : $6x^2 + 4x=4x+6x^2$

So the given algebraic expression is a commutative property of operations. The commutative property states that when any two numbers are added in an expression the sum of the numbers are the same regardless of the order of the numbers that are added.

Thus the sum of the above expression will be same in which ever order the numbers are added.

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A building 190 feet tall casts a 90 foot long shadow. if a person stands at the end of the shadow and looks up to the top of the

Ivahew [28]

Answer:

About 64.65 degrees

Step-by-step explanation:

$\tan(x) = \frac{190}{90}$

$x = { \tan}^{ - 1} \frac{190}{90} = 64.65$

Make sure your calculator is in degree mode.

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2 years ago

For this graph, mark the statements that are true.

Goshia [24]

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Step-by-step explanation:

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3 years ago

Describe the graph of y = 3x and compare it with the graph of y = x,

kykrilka [37]

check math way

Step-by-step explanation: it helps more then here

7 0

3 years ago

Please help!

crimeas [40]

Answer:

The zeros are:

$x =4, x=2, x = 5$

The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

$h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)$

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

$0=\left(x-4\right)^2\left(x^2-7x+10\right)$

switch sides

$\left(x-4\right)^2\left(x^2-7x+10\right)=0$

$x^2-7x+\:10=\left(x-2\right)\left(x-5\right)$

$\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0$

Using the zero factor principle

$\mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

$x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0$

$x =4, x=2, x = 5$

Thus, the zeros are:

$x =4, x=2, x = 5$

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

The function has three distinct real zeros.

Hence, option (B) is true.

4 0

3 years ago

Thomas wants to invite Madeline to a party. He has an 80% chance of bumping into her at school. Otherwise, he’ll call her on the

Alexandra [31]

Answer:

84%

Step-by-step explanation:

The probability of Thomas bumping into her at school is 80%, so the probability of not bumping into her is 100% - 80% = 20%.

If he doesn't bump into her (20% chance), he will call her, and the probability of asking her in this case is 60%, so the final probability of asking her in this case is:

$P_1 = 20\% * 60\% = 12\%$

If he bumps into her (80% chance), the probability of asking her is 90%, so the final probability of asking her in this case is:

$P_2 = 80\% * 90\% = 72\%$

To find the probability of Thomas inviting Madeline to the party, we just have to sum the probabilities we found above:

$P = P_1 + P_2$

$P = 12\% + 72\% = 84\%$

5 0

3 years ago