Answer:
A 2-column table with 6 rows. Column 1 is labeled x with entries 1.99, 1.999, 1.9999, 2.0001, 2.001, 2.01. Column 2 is labeled f (x) with entries 0.505, negative 0.827, 0.306, negative 0.306, 0.827, negative 0.506.
Find Limit of f (x) as x approaches 2 f(x), if it exists.
2
0.3
0
DNE
Let's simplify step-by-step.
<span><span>9−x</span>−<span>(<span>7+x</span>)
</span></span>Distribute the Negative Sign:
<span>=<span><span>9−x</span>+<span><span>−1</span><span>(<span>7+x</span>)
</span></span></span></span><span>=<span><span><span><span>9+</span>−x</span>+<span><span>(<span>−1</span>)</span><span>(7)</span></span></span>+<span><span>−1</span>x
</span></span></span><span>=<span><span><span><span><span><span>9+</span>−x</span>+</span>−7</span>+</span>−x
</span></span>Combine Like Terms:
<span>=<span><span><span>9+<span>−x</span></span>+<span>−7</span></span>+<span>−x
</span></span></span><span>=<span><span>(<span><span>−x</span>+<span>−x</span></span>)</span>+<span>(<span>9+<span>−7</span></span>)
</span></span></span><span>=<span><span>−<span>2x</span></span>+2
</span></span>Answer:
<span>=<span><span>−<span>2x</span></span>+<span>2</span></span></span>
I'm pretty sure its D but im not too sure. Sorry about that :/
Just turn a negative number into a positive number