Answer:
x=1
y=s
z=1
Step-by-step explanation:
(x, y, z)=(1, 0, 1)
Substitute 0 for y
Confirming if t=0 satisfy the other equation
x = e^−2t cos 4t = e^−2(0)cos(4*0)
= e^(0)cos(0) = 1
z = e^−2t = e^−2(0) = 0
Therefore t=0 satisfies the other equation
Finding the tangent vector at t=0
The vector equation of the tangent line is
(1, 0, 1) +s(0,1,0)= (1, s, 1)
The parametric equations are:
x=1
y=s
z=1
If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
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