1ll mark brainlist pleassee help

(03.05 MC)

vagabundo [1.1K]

Answer:

I can not answer for some reason

i am so so sorry i really was trying

Step-by-step explanation:

6 0

2 years ago

Additive inverse of 400

Goshia [24]

Given:

A number is 400.

To find:

The additive inverse of 400.

Solution:

We know that the sum of a number and its additive inverse is 0.

If "a" is number and "b" is its additive inverse, then

$a+b=0$

Let x be the additive inverse of 400. Then,

$400+x=0$

Subtract both sides by 400.

$400+x-400=0-400$

$x=-400$

Therefore, the additive inverse of 400 is $-400$ .

7 0

3 years ago

I need help I don’t understand

zimovet [89]

Answer:

Decreases

Step-by-step explanation:

As 'n' increases the value of the (1/4) will decrease.

Say, n=1 ; 1/4

n=2 ; 1/4 * 1/4 = 1/16(because n=2, there are two 1/4s)

n= and so on

3 0

2 years ago

For the following linear system, put the augmented coefficient matrix into reduced row-echelon form.

Anni [7]

Answer:

The reduced row-echelon form of the linear system is $\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

Step-by-step explanation:

We will solve the original system of linear equations by performing a sequence of the following elementary row operations on the augmented matrix:

Interchange two rows
Multiply one row by a nonzero number
Add a multiple of one row to a different row

To find the reduced row-echelon form of this augmented matrix

$\left[\begin{array}{cccc}2&3&-1&14\\1&2&1&4\\5&9&2&7\end{array}\right]$

You need to follow these steps:

Divide row 1 by 2 $\left(R_1=\frac{R_1}{2}\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\1&2&1&4\\5&9&2&7\end{array}\right]$

Subtract row 1 from row 2 $\left(R_2=R_2-R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\5&9&2&7\end{array}\right]$

Subtract row 1 multiplied by 5 from row 3 $\left(R_3=R_3-\left(5\right)R_1\right)$

$\left[\begin{array}{cccc}1&3/2&-1/2&7\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 1 $\left(R_1=R_1-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&3/9&9/2&-28\end{array}\right]$

Subtract row 2 multiplied by 3 from row 3 $\left(R_3=R_3-\left(3\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&1/2&3/2&-3\\0&0&0&-19\end{array}\right]$

Multiply row 2 by 2 $\left(R_2=\left(2\right)R_2\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&-19\end{array}\right]$

Divide row 3 by −19 $\left(R_3=\frac{R_3}{-19}\right)$

$\left[\begin{array}{cccc}1&0&-5&16\\0&2&3&-6\\0&0&0&1\end{array}\right]$

Subtract row 3 multiplied by 16 from row 1 $\left(R_1=R_1-\left(16\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&-6\\0&0&0&1\end{array}\right]$

Add row 3 multiplied by 6 to row 2 $\left(R_2=R_2+\left(6\right)R_3\right)$

$\left[\begin{array}{cccc}1&0&-5&0\\0&1&3&0\\0&0&0&1\end{array}\right]$

8 0

3 years ago

Aubrey can walk 4 1/2 miles in 1 1/2 hours. Find her average speed in miles per hour.

Naddik [55]

Time = 11/2 = 5 1/2
Road = 4 1/2 miles
Speed = 5 1/2 : 4 1/2 = 1 2/9 <------------answer

4 0

3 years ago

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