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2 years ago

Find the slope of 5x-2y=-2

Mathematics

2 answers:

Keith_Richards [23]2 years ago

7 0

<h2>Answer:</h2><h2>The slope is 5/2</h2><h2 /><h2>Hope this helps!!</h2>

pochemuha2 years ago

4 0

Answer:

5/2

Step-by-step explanation:

Ik the answer. Pretty good at algebra so trust me.

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Zielflug [23.3K]

The answer to your question is 3.

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3 years ago

Find the total cost of a $363.99 airline ticket with sales tax of 4%

Harman [31]

4% means 4100 'of' means multiply so:

363.99⋅4100 is 363.99⋅4 = 1455.96

1455.96100 = 14.56 (rounded up)

363.99+14.56=$378.55 to the nearest cent.

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3 years ago

Really struggling with this one. Can someone help please?

krek1111 [17]

Answer:

Step-by-step explanation:

M is in the middle between S and T we know 2x+6 has to be the same as 3x+3 if 3x is one more x then 2x then we do 6-3 that eqauls 3 so X=3 and 2*3=6 and 6+6= 12.

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3 years ago

Read 2 more answers

4. A small high school holds its graduation ceremony in the gym. Because of seating constraints, students are limited to a maxim

Ad libitum [116K]

Answer:

(a) The mean and standard deviation of X is 2.6 and 1.2 respectively.

(b) The mean and standard deviation of T are 390 and 180 respectively.

(c) The distribution of T is N (390, 180²). The probability that all students’ requests can be accommodated is 0.7291.

Step-by-step explanation:

(a)

The random variable X is defined as the number of tickets requested by a randomly selected graduating student.

The probability distribution of the number of tickets wanted by the students for the graduation ceremony is as follows:

X P (X)

0 0.05

1 0.15

2 0.25

3 0.25

4 0.30

The formula to compute the mean is:

$\mu=\sum x\cdot P(X)$

Compute the mean number of tickets requested by a student as follows:

$\mu=\sum x\cdot P(X)\\=(0\times 0.05)+(1\times 0.15)+(2\times 0.25)+(3\times 0.25)+(4\times 0.30)\\=2.6$

The formula of standard deviation of the number of tickets requested by a student as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}$

Compute the standard deviation as follows:

$\sigma=\sqrt{E(X^{2})-\mu^{2}}\\=\sqrt{[(0^{2}\times 0.05)+(1^{2}\times 0.15)+(2^{2}\times 0.25)+(3^{2}\times 0.25)+(4^{2}\times 0.30)]-(2.6)^{2}}\\=\sqrt{1.44}\\=1.2$

Thus, the mean and standard deviation of X is 2.6 and 1.2 respectively.

(b)

The random variable T is defined as the total number of tickets requested by the 150 students graduating this year.

That is, T = 150 X

Compute the mean of T as follows:

$\mu=E(T)\\=E(150\cdot X)\\=150\times E(X)\\=150\times 2.6\\=390$

Compute the standard deviation of T as follows:

$\sigma=SD(T)\\=SD(150\cdot X)\\=\sqrt{V(150\cdot X)}\\=\sqrt{150^{2}}\times SD(X)\\=150\times 1.2\\=180$

Thus, the mean and standard deviation of T are 390 and 180 respectively.

(c)

The maximum number of seats at the gym is, 500.

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and we take appropriately huge random samples (n ≥ 30) from the population with replacement, then the distribution of the sum of values of X, i.e ∑X, will be approximately normally distributed.

Here T = total number of seats requested.

Then, the mean of the distribution of the sum of values of X is given by,

$\mu_{T}=n\times \mu_{X}=390$

And the standard deviation of the distribution of the sum of values of X is given by,

$\sigma_{T}=n\times \sigma_{X}=180$

So, the distribution of T is N (390, 180²).

Compute the probability that all students’ requests can be accommodated, i.e. less than 500 seats were requested as follows:

$P(T$

Thus, the probability that all students’ requests can be accommodated is 0.7291.

8 0

3 years ago

6. Fatima bought a XBOX game that is $38.00 plus 9%

Vesna [10]

Answer:

Total sales tax = $3.42

Step-by-step explanation:

Total sales tax = Item or service cost × sales tax

TST = IC × ST

Item cost = $38.00

Sales Tax = 9%

= $\frac{9}{100}$

= 0.09

Total sales Tax = 38 × 0.09

= $3.42

4 0

3 years ago