Answer:
The null hypothesis is not rejected and hence Type II error occurred
Step-by-step explanation:
Here
The null hypothesis is as follows
H0 = Mean = 0.5
The alternate hypothesis is as follows -
H1 = Mean >0.5
For Type I error = The Null hypothesis is rejected if null hypothesis is actually true
Type II error =The Null hypothesis is not rejected when the null hypothesis is not true but is false.
Here, the null hypothesis is not rejected and hence Type II error occurred
Answer:
In the ATTACHMENT
Step-by-step explanation:
For the first one, you can plug in multiple numbers of any kind for 
and start to form you line.
For the second one, know that the 
line is always horizontal. Find -3 on the plot that would be on the 
and put that horizontal line on it.
<em>Hope this helps!!</em>
Just add 16 to -3, then that will get your answer 13.
Here the only limitation on the domain exists when the denominator is equal to zero, as division by zero has no meaning and is not "allowed" because of its meaninglessness. :)
Factor the denominator to find the excluded values of x...
3x^2+5x-12
3x^2+9x-4x-12
3x(x+3)-4(x+3)
(3x-4)(x+3)
So x CANNOT equal 4/3 or -3 (all other real values of x are part of the domain) so the domain is:
x=(-oo, -3),(-3, 4/3),(4/3, +oo)
