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enot [183]
3 years ago
14

Ryan has 25 tiles and 12% of them are green. how many tiles are green

Mathematics
1 answer:
Lady_Fox [76]3 years ago
6 0

Answer:

208.33. this is it your welcome

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I need help if 12 counters are 3/4of a set then what is the whole set
jeyben [28]
12 = 3/4 * x
12 ÷ 3/4 = x
12 * 4/3 = x
48/3 = x
16 = x

Answer: The whole set is 16 counters
5 0
3 years ago
Read 2 more answers
What is 12 1/4`÷7/8
Sidana [21]

Answer:

14

Divide

12 and 1 over 412

1

4

÷ 7 over 8

7

8

= 392 over 28

392

28

Step 1 of 2: Divide, sub-step a: Convert mixed number to improper fraction.

Convert mixed number to improper fraction

12 and 1 over 412

1

4

= ( 12 × 4 ) over 4

12 × 4

4

+ 1 over 4

1

4

= ( 48 + 1 ) over 4

48 + 1

4

= 49 over 4

49

4

Step 1 of 2: Divide, sub-step b: Divide.

Divide

49 over 4

49

4

÷ 7 over 8

7

8

= 49 over 4

49

4

× 8 over 7

8

7

= ( 49 × 8 ) over ( 4 × 7 )

49 × 8

4 × 7

= 392 over 28

392

28

To divide fractions, invert the second one (turn it upside-down), then multiply the numerators and denominators.Divide

12 and 1 over 412

1

4

÷ 7 over 8

7

8

= 392 over 28

392

28

Step 1 of 2: Divide, sub-step a: Convert mixed number to improper fraction.

Convert mixed number to improper fraction

12 and 1 over 412

1

4

= ( 12 × 4 ) over 4

12 × 4

4

+ 1 over 4

1

4

= ( 48 + 1 ) over 4

48 + 1

4

= 49 over 4

49

4

Step 1 of 2: Divide, sub-step b: Divide.

Divide

49 over 4

49

4

÷ 7 over 8

7

8

= 49 over 4

49

4

× 8 over 7

8

7

= ( 49 × 8 ) over ( 4 × 7 )

49 × 8

4 × 7

= 392 over 28

392

28

To divide fractions, invert the second one (turn it upside-down), then multiply the numerators and denominators.

4 0
3 years ago
Solve 2(x + 1) = 2x + 2.
Tom [10]

2(x + 1) = 2x + 2\\\\
2x+2=2x+2\\\\
x\in\mathbb{R}

3 0
3 years ago
(r-3)(r-1)<br> Help me please!!!
madreJ [45]

Answer:

= r²−4r+3

Step-by-step explanation:

(r - 3) (r - 1)

(r x r) + (r x -1) + (-3 x r) + (-3 x -1)

r² + - r - 3r + 3

= r²−4r+3

5 0
3 years ago
Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

7 0
3 years ago
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