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3 years ago

Ryan has 25 tiles and 12% of them are green. how many tiles are green

Mathematics

1 answer:

Lady_Fox [76]3 years ago

6 0

Answer:

208.33. this is it your welcome

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What is the product of 2x + y and 5x – y + 3?

Radda [10]

Answer:

The product of 2x + y and 5x – y + 3 is 10x^2+ 3xy + 6x - y^2 + 3y

Step-by-step explanation:

The product of the two expressions can be expressed mathematically as;

(2x +y) (5x -y +3)

To obtain the product of these expressions, we simply expand the brackets as follows;

2x(5x -y +3) + y(5x -y +3)

= 10x^2 - 2xy + 6x + 5xy - y^2 + 3y

= 10x^2- 2xy + 5xy + 6x - y^2 + 3y

= 10x^2+ 3xy + 6x - y^2 + 3y

The product of 2x + y and 5x – y + 3 is thus 10x^2+ 3xy + 6x - y^2 + 3y

5 0

2 years ago

Read 2 more answers

Is 85/95 greater than 64/76

madam [21]

85/95 is equal to 0.8947
64/76 is equal to 0.842
Therefore, 85/95 is greater

5 0

3 years ago

16. What will be the midpoint of AB with A= (-3,-8) and B = (-9,-8)

mihalych1998 [28]

The answer is: (-6,-8)

7 0

3 years ago

1. The population of a small town has established a growth rate of 3% per year. If the

Rasek [7]

Answer:

17 years

Step-by-step explanation:

3% of 2000 = 60

3000-200 = 1000

1000 ÷ 60= 16.6666666667

Round to the nearest whole number: 17

8 0

3 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

3 years ago