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svet-max [94.6K]
2 years ago
10

HELP ASAP PLEASE!

Mathematics
1 answer:
tatyana61 [14]2 years ago
7 0
M= (y2-y1)/(x2-x1)

Plug in the points. (2,3) (9,7)

m= (7-3)/(9-2)

m= 4/7

Slope= 4/7

I hope this helps!
~kaikers
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Segment lm is the midsegment of trapezoid abcd. ab = 58, and dc = 98. what is lm?
kifflom [539]
Lm would be 78 because it is halfway between ab and dc and 98-58=40 and half of 40=20, so 58+20=78 or 98-20=78.
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A.

C.

Step-by-step explanation:

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2 years ago
1. {-7, -3, -9/11, √9, 18/5}
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Step-by-step explanation:

I hope it will help you

7 0
2 years ago
Read 2 more answers
A land owner is planning to build a fenced-in, rectangular patio behind his garage, using his garage as one of the "walls." He
Vitek1552 [10]

Answer:

Maximum area = 800 square feet.

Step-by-step explanation:

In the figure attached,

Rectangle is showing width = x ft and the side towards garage is not to be fenced.

Length of the fence has been given as 80 ft.

Therefore, length of the fence = Sum of all three sides of the rectangle to be fenced

80 = x + x + y

80 = 2x + y

y = (80 - 2x)

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Or function that represents the area of the rectangle is,

A(x) = x(80 - 2x)

A(x) = 80x - 2x²

To find the maximum area we will take the derivative of the function with respect to x and equate it to zero.

A'(x)=\frac{d}{dx}(80x-2x^{2})

             = 80 - 4x

A'(x) = 80 - 4x = 0

4x = 80

x = \frac{80}{4}

x = 20

Therefore, for x = 20 ft area of the rectangular patio will be maximum.

A(20) = 80×(20) - 2×(20)²

         = 1600 - 800

         = 800 square feet

Maximum area of the patio is 800 square feet.

7 0
3 years ago
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