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Lubov Fominskaja [6]
4 years ago
14

A meter stick flies by with an apparent length of 60 cm. What is it's velocity in m/s? Not sure which formula to use

Physics
2 answers:
EastWind [94]4 years ago
7 0
Starting with g <span>equal to (1/0.6), solve for v.

</span>
vichka [17]4 years ago
4 0

Solution:

<span>Starting with </span>g <span>equal to (1/0.6), solve for v.</span>

<span>v = 0.8c = 2.4E8 m/s</span>


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An inexperienced researcher runs an experiment and sets his alpha level at .40 because he can't wait to get his firstsignificant
GuDViN [60]

A potential problem is that you are willing to accept a <u>5% </u>chance of being wrong if you reject the null hypothesis.

The significance level is the probability of rejecting the null hypothesis if it is true. For example, a significance level of 0.05 indicates a 5% risk of concluding that there is a difference when there is actually no difference. Rejecting the true null hypothesis results in a Type I error.

The smaller the value of α the more difficult it is to reject the null hypothesis. Therefore, choosing a low value for α can reduce the likelihood of Type I errors. The result here is that if the null hypothesis is false, it may be more difficult to reject using a lower value for α. The alpha value or statistical significance threshold is arbitrary. Which value to use depends on your field of study.

Learn more about The potential problems here:-brainly.com/question/21836542

#SPJ4

4 0
1 year ago
A sled plus passenger with total mass m = 52.3 kg is pulled a distance d = 21.8 m across a horizontal, snow-packed surface for w
Vikki [24]

Answer:

Explanation:

Since the sled plus passenger moves with constant velocity , force applied will be equal to frictional force. Let the force applied be F

a ) Frictional force = μ R = F cosφ

R = mg - F sinφ

μ(mg - F sinφ)  = F cosφ

μmg = F (μsinφ+cosφ)

F = μmg / (μsinφ+cosφ)

Work done

= F cosφ x d

= μmg x cosφ x d / (μsinφ+cosφ)

b )Work done

= 0.13 x 52.3 x 9.8 cos36.7 x 21.8 / ( 0.13 sin36.7 +cos36.7)

= 1164.61 / .87946

1324.23 J

c ) work done on the sled by friction

= - (work done by force)

= - μmg x cosφ x d / (μsinφ+cosφ)

d ) work done on the sled by friction

= - 1324.23 J

3 0
3 years ago
An ideal spring obeys Hooke’s law, F~ = −k~x. A mass of 0.50 kilogram hung vertically from this spring stretches the spring 0.07
masha68 [24]

The spring constant is 66.7 N/m

Explanation:

First of all, we have to find the magnitude of the force acting on the spring. This is equal to the weight of the mass hanging on the spring, which is:

F=mg

where:

m = 0.50 kg is the mass of the object

g=10 m/s^2 is the acceleration of gravity

Substituting,

F=(0.50)(10)=5 N

Now we can use Hookes' law to find the constant of the spring:

F=-kx

where

F is the force applied

k is the spring constant

x is the stretching of the spring

Here we have:

F = 5 N

While the stretching is

x = 0.075 m

Therefore, ignoring the negative sign in the formula (which only tells us the direction), we find the spring constant:

k=\frac{F}{x}=\frac{5}{0.075}=66.7 N/m

#LearnwithBrainly

5 0
3 years ago
An input force is applied to a 2 cm diameter piston. The piston compresses oil and is connected to a 4 cm diameter output piston
____ [38]

Answer:

4 times

Explanation:

Given:

diameter of the input piston, d_i=2\ cm=0.02\ m

diameter of the output piston, d_o=4\ cm=0.04\ m

In such mechanical arrangements the fluid acts as an incompressible link and the pressure remains uniform throughout the fluid bulk.

Then, by the Pascal's law:

\frac{F_i}{A_i} =\frac{F_o}{A_o}

where:

F_i\ \&\ F_o are the input and the output forces respectively.

A_i\ \&\ A_o are the input and the output area of pistons respectively.

\frac{F_i\times 4}{\pi.d_i^2} =\frac{F_o\times 4}{\pi.d_o^2}

\frac{F_i}{d_i^2} =\frac{F_o}{d_o^2}

\frac{F_o}{0.04^2}=\frac{F_i}{0.02^2}

F_o=4\times F_i

8 0
3 years ago
me (5) A taxi is travelling at 15. m/s. Its driver accelerates with acceleration 3 m/s for 4 s. What is its new velocity? A car
photoshop1234 [79]

Answer:

5)

Solution

initial velocity = 15 m/s

acceleration = 3m/s^2

time = 4 s

final velocity = 15+3×4

=15+12

=27m/s

A car accelerates from 20m/s to 30m/s in 10 second

T9 be honest I think some part of the second question is missing

4 0
3 years ago
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