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S_A_V [24]
4 years ago
9

An input force is applied to a 2 cm diameter piston. The piston compresses oil and is connected to a 4 cm diameter output piston

. The force on the output piston is ________ the force on the input piston. (Select all that apply.)
Physics
1 answer:
____ [38]4 years ago
8 0

Answer:

4 times

Explanation:

Given:

diameter of the input piston, d_i=2\ cm=0.02\ m

diameter of the output piston, d_o=4\ cm=0.04\ m

In such mechanical arrangements the fluid acts as an incompressible link and the pressure remains uniform throughout the fluid bulk.

Then, by the Pascal's law:

\frac{F_i}{A_i} =\frac{F_o}{A_o}

where:

F_i\ \&\ F_o are the input and the output forces respectively.

A_i\ \&\ A_o are the input and the output area of pistons respectively.

\frac{F_i\times 4}{\pi.d_i^2} =\frac{F_o\times 4}{\pi.d_o^2}

\frac{F_i}{d_i^2} =\frac{F_o}{d_o^2}

\frac{F_o}{0.04^2}=\frac{F_i}{0.02^2}

F_o=4\times F_i

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A 10-cm-thick aluminum plate (α = 97.1 × 10−6 m2/s) is being heated in liquid with temperature of 475°C. The aluminum plate has
Anuta_ua [19.1K]

Answer:

T_0 = 338.916 Degree\ celcius

Explanation:

Given data:

Thickness of aluminium sheet 10 cm

initial temperature = 25 degree celcius

Assumption

Thermal properties remain constant, transfer of heat by radiation is negligible.

from the information given in the question we have

T_S ≈T_∞ , it implies we have h → ∞

from table 4.2 Biot number → ∞ the value of

\lambda_1 = 1.5708 and A_1= 1.2732

The fourier number is

t = \frac{\alpha t}{l^2} = \frac{97.1\times 10^{-6} \times 15}{0.05^2} = 0.5826

Temperature at center after 15 second of heating

\theta _{0 wall} = \frac{T_0 - T_{\infity}}{T_i -T_{\infity}} = A_i e^{\lambda_1^2 t}

T_0 = T_i -T_{\infity} \times A_i e^{\lambda_1^2 t}

T_0 = (25 - 475) 1.2732 e^{-1.5708^2 \times 0.5826} +  475  = 356 degree celcius

T_0 = 338.916 Degree\ celcius

8 0
3 years ago
Rocks that are formed as a result of deposits from weathering and erosion
zimovet [89]
<h2>Answer: Sedimentary rocks </h2>

Sedimentary rocks are formed from sediments and deposits of particles of various types, forms and sizes that are transported by air, wind or water, and then subjected to chemical processes to become rocks.

These types of rocks are usually found in the form of layers or strata in places where sediment accumulates due to the erosion of other materials, for example on the banks of rivers, in valleys, lakes (and any other type of body of water).

8 0
3 years ago
A 50.0 g toy car is released from rest on a frictionless track with a vertical loop of radius R (loop-the-loop). The initial hei
Mariana [72]

Answer:

the speed of the car at the top of the vertical loop  v_{top} = 2.0 \sqrt{gR \ \ }

the magnitude of the normal force acting on the car at the top of the vertical loop   F_{N} = 1.47 \ \ N

Explanation:

Using the law of conservation of energy ;

mgh = mg (2R) + \frac{1}{2}mv^2_{top}\\\\mg ( 4.00 \ R) = mg (2R) + \frac{1}{2}mv^2_{top}\\\\g(4.00 \ R) = g (2R) + \frac{1}{2}v^2 _{top}\\\\v_{top} = \sqrt{2g(4.00R - 2R)}\\\\v_{top} = \sqrt{2g(4.00-2)R

v_{top} = 2.0 \sqrt{gR \ \ }

The  magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:

F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\

F_{N} = 1.47 \ \ N

4 0
4 years ago
What tempature does stone turn to lava?
rosijanka [135]
I would say 1000c as my answer
5 0
4 years ago
Calculate the force of attraction between
vagabundo [1.1K]

Answer:

So the force of attraction between the two objects is 3.3365*10^-6

Explanation:

m1=10kg

m2=50kg

d=10cm=0.1m

G=6.673*10^-11Nm^2kg^2

We have to find the force of attraction between them

F=Gm1m2/d^2

F=6.673*10^-11*10*50/0.1^2

F=3.3365*10^-8/0.01

F=3.3365*10^-6

4 0
4 years ago
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