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3 years ago

8

A 13m long ladder when set against the well of a house reacher a height of 12m. How far is the foot of the ladder from the wall

2 answers:

Leokris [45]3 years ago

6 0

Answer:

half a metre

Step-by-step explanation:

Elenna [48]3 years ago

3 0

13^2-12^2=25
Square root 25 which is 5
Answer is 5 meters

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PLEASE NEED HELP PROPOTION AND PERCENTS !!!WILL GIVE BEST RATE

vlabodo [156]

Answer:

80

Step-by-step explanation:

40 is 100

32 is x

100*32/40=80

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3 years ago

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What is the equation of the line that passes through the points (-1, 1.5) and (0.5, 0.5)

Step2247 [10]

The slope-point formula:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have:

$(-1,\ 1.5)\to x_1=-1,\ y_1=1.5\\(0.5,\ 0.5)\to x_2=0.5,\ y_2=0.5$

Substitute:

$m=\dfrac{0.5-1.5}{0.5-(-1)}=\dfrac{-1}{1.5}=-\dfrac{1}{\frac{3}{2}}=-\dfrac{2}{3}\\\\y-1.5=-\dfrac{2}{3}(x-(-1))\\\\y-1.5=-\dfrac{2}{3}x-\dfrac{2}{3}\\\\y-\dfrac{3}{2}=-\dfrac{2}{3}x-\dfrac{2}{3}\ \ \ |+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2}{3}+\dfrac{3}{2}\\\\y=-\dfrac{2}{3}x-\dfrac{2\cdot2}{3\cdot2}+\dfrac{3\cdot3}{2\cdot3}\\\\y=-\dfrac{2}{3}x-\dfrac{4}{6}+\dfrac{9}{6}\\\\y=-\dfrac{2}{3}x+\dfrac{5}{6}$

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3 years ago

PLEASE ANSWER !

ivanzaharov [21]

Answer:I think no, because 25+35+45=150. 150x3=450

Maybe, for 4 months he'd have enough. So, 150x4=600. So Jamal would have some extra money!

Step-by-step explanation:

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4 years ago

Julio has started his very own floral business. He sells centerpieces for $19.50 each. His fixed costs are $500 per month, and e

Phantasy [73]

The total cost, C, is the sum of the cost to produce the centerpieces and the fixed cost. The equation for C is C = 8n + 500.

The total revenue, R, of Julio's floral business is the product of the cost per centerpiece and the number of centerpieces sold. The equation for R is R = 19.50n.

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4 years ago

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Ksju [112]

Answer:

domain is {4,5,6,7,8}, range is the other numbers in brackets

Step-by-step explanation:

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2 years ago