Let a and b be the numbers,then a+b=32,b=32-a
ab=-320
a(32-a)=-320
32a-a^2=-320
a^2-32a-320=0
a^2-40a+8a-320=0
a(a-40)+8(a-40)=0
(a-40)(a+8)=0
a=40 or-8
when a=40,b=32-40=-8
when a=-8,b=32-(-8)=32+8=40
so numbers are 40 and -8
Answer:
40c +20
Step-by-step explanation:
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Answer:
A
Step-by-step explanation:
I am pretty sure this is right and I hope this helps
Answer: y=2x-1
We know that the equation of a line is y = mx + b, where m is the gradient and b is the y-intercept.
First to find the gradient, we use the formula y2-y1/x2-x1.
x1 and y1 being the first set of coordinates (2,3) and x2 and y2 being the second set (4,7)
Now we sub in:
m=7-3/4-2
m=4/2
m=2
This is our gradient and we can put it into the equation: y=2x+b
Now we find the y-intercept (b). Since the y-intercept isn’t shown, we can sub in the coordinates to find it.
y=2x+b
Sub (2,3)
3=2(2)+b
3=4+b
-1=b
Sub (4,7)
7=2(4)+b
7=8+b
-1=b
Subbing in both coordinates gives us -1 as the y-intercept, so the finished equation is: y=2x-1
