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3 years ago

Please do part b A=5 and B=4

Mathematics

2 answers:

tatyana61 [14]3 years ago

4 0

Answer:

you have the answer already

Step-by-step explanation:

Scilla [17]3 years ago

3 0

Rectangle is 72

The square is 45

The length for A is 8

The length for B is 3

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You are assigned a computer generated 4-digit password to access your new voice mail account. If the

lara [203]

Answer:

5,040 different passwords are possible

Step-by-step explanation:

Assuming that 4-digit means using only numeric values.

This is a permutations problem.

n = number of values used with number values only this is 10

r = the number used in each case without repeating in this case 4

nPr = n! / (n - r)!

nPr = 10! / (10-4)!

nPr = 10! / 6!

The ! means factorial. For example 4! = 4 x 3 x 2 x 1 = 24

A quick hack for dividing factorials is to use cancelling.

10! / 6! = 10 x 9 x 8 x 7 (because 6 to 1 are cancelled by 6!)

= 5040

5 0

4 years ago

A researcher plans to ask employees whether they favor, oppose, or are indifferent about a change in the company retirement prog

dexar [7]

Answer:

Hypothesis Testing

Step-by-step explanation:

The null hypothesis may be created as follows:

"The employees of the company favor the company retirement program."

For testing, the research will most probably use a survey questionnaire. Hence, the survey question for this purpose would be a multiple-option question that would read as follows:

I favor the stated change in the company retirement program.

Strongly Disagree
Disagree
Neutral
Agree
Strongly Agree

4 0

4 years ago

Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

A bad contains pennies, nickels, dimes, and quarters. There are 50 coins in all. Of the coins, 14% are pennies are 32% are dimes

Contact [7]

Answer:

$6.22

Step-by-step explanation:

Given;

Total number of coins N = 50

Number of pennies p = 14% of N = 0.14 × 50 = 7

Number of dimes d = 32% of N = 0.32×50 = 16

Number of nickels n = 4 + number of pennies = 4+p

n = 4+7 = 11

Number of quarters q;

N = p+d+n+q

q = N - (p+d+n)

q = 50-(7+16+11)

q = 16

1 Penny = 1 cent = $0.01

1 Nickel = 5 cent = $0.05

1 dime = 10 cents = $0.10

1 quarter = 25 cents = $0.25

Total amount in the bag is;

C = 0.01p + 0.05n + 0.10d +0.25q

Substituting the values;

C = 0.01(7) + 0.05(11) + 0.10(16) + 0.25(16)

C = $6.22

The bag contains $6.22

7 0

3 years ago

Read 2 more answers

Z=8+6x-px<br><br>solve for x

ohaa [14]

z = 8 + 6x - px Subtract 8 from both sides
z - 8 = 6x - px Factor the x out of 6x - px
z - 8 = x (6 - p) Divide both sides by (6 - p)
$\frac{z - 8}{6 - p}$ = x Switch the sides to make it easier to read
x = <span> $\frac{z - 8}{6 - p}$ </span>

4 0

4 years ago

Read 2 more answers