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Answer:
b) no solution
Step-by-step explanation:
What you always want to do in this type of problem is to combine all of your "like terms," where like terms are the part of your equation that have the same variable (or no variable). In this equation, we see three terms that have the variable "z". We can add the 12z + 15z on the left side to get 27z, and then we subtract 27z on both sides to cancel both of the 27z terms out.
Now, we are left with -6 = -5 (because we got rid of all the terms with the variable z in them). We know that -6 does not equal -5, and therefore, there is no number that we can assign to variable z such that the left side of the equation will equal the right side of the equation.
Therefore, there is no solution (because a solution to the equation would be a value that we can plug into the variable z to make the equation true).
Answer:
<em>(8.21, -20.79)</em>
Step-by-step explanation:
Given the simultaneous equation;
From 2;
a = 29 + b ....3
Substitute 3 into 1;
Factorize
b = -18±√18²-4(-58)/2
b = -18±√324+232/2
b = -18±√556/2
b = -18±23.58/2
b = -18-23.58/2 and -18+23.58/2
b = -41.58/2 and 5.58/2
b = -20.79 and 2.79
Since a = 29 + b
when b = -20.79
a = 29 - 20.79
a = 8.21
<em>Hence the solution to the system of equation is (8.21, -20.79)</em>
Answer:
In step by step explanation
Step-by-step explanation:
Move your decimal until you have one non-zero number left of your deciaml point the number of times you moved you decimal to the left will be the exponent you put attached to a ten.
