2 digit number with the sum being 11
possibilities are : 2 and 9......3 and 8......4 and 7.....5 and 6
the 10 digit is 3 more then the 1 digit
ur number is : 74 <==
We will use integration by substitution, as well as the integrals
∫
1
x
d
x
=
ln
|
x
|
+
C
and
∫
1
d
x
=
x
+
C
∫
x
3
x
2
+
1
d
x
=
∫
x
2
x
2
+
1
x
d
x
=
1
2
∫
(
x
2
+
1
)
−
1
x
2
+
1
2
x
d
x
Let
u
=
x
2
+
1
⇒
d
u
=
2
x
d
x
. Then
1
2
∫
(
x
2
+
1
)
−
1
x
2
+
1
2
x
d
x
=
1
2
∫
u
−
1
u
d
u
=
1
2
∫
(
1
−
1
u
)
d
u
=
1
2
(
u
−
ln
|
u
|
)
+
C
=
x
2
+
1
2
−
ln
(
x
2
+
1
)
2
+
C
=
x
2
2
−
ln
(
x
2
+
1
)
2
+
1
2
+
C
=
x
2
−
ln
(
x
2
+
1
)
2
+
C
Final answer
Answer:
<em>hey </em>
Step-by-step explanation:
which u r studying inn
Use the compound amount formula:
A = P(1+r)^t
Here, A = £2000 (1+0.03)^2 = <span>£2121.80 (answer)</span>
B=7
3(b-4)+5b=44
3b-12+5b=44
8b=44+12
8b=56
b=7
