Answer:
The period when its more than halfway
= 2 < t ≤ 2.83 seconds ( to nearest hundredth).
Step-by-step explanation:
When is is halfway down the ramp d = 3920/2 = 1960 cm, so:
1960 = 490 t^2
t^2 = 1960/490 = 4
t = 2 seconds.
When it reaches the bottom d = 3920 :
t^2 = 3920/490 = 8
t = 2.83 seconds.
Answer:-2,-3
Step-by-step explanation:
Answer:
hx-h2+6
Step-by-step explanation:
First solve the parentheses, do h*x - 2h, then add the +6.
Hope I helped! :D
Let the two numbers be represented by x and y. The problem statement gives rise to two sets of equations.
x - y = 0.6
y/x = 0.6 . . . . . . . assuming x is the larger of the two numbers
or
x/y = 0.6 . . . . . . . assuming y has the larger magnitude
The solution of the first pair of equations is
(x, y) = (1.5, 0.9)
The solution of the first and last equations is
(x, y) = (-0.9, -1.5)
The pairs of numbers could be {0.9, 1.5} or {-1.5, -0.9}.
