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iren2701 [21]
3 years ago
12

X and Y together can do a piece of work in 10 days and X alone can do it in 15 days would Y alone can finish the work ?​

Mathematics
1 answer:
Ratling [72]3 years ago
8 0

Answer:

<em>Y alone can do the piece of work in 30 days.</em>

Step-by-step explanation:

<u>Proportions</u>

Let's make:

N = days for Y to finish the work alone

Since X alone can do it in 15 days, each day he can do a proportion of 1/15 of the piece of work.

Since Y alone can (possibly) do it in N days, each day he can do 1/N parts of the work.

Together, they do

\displaystyle \frac{1}{15}+\frac{1}{N}

parts of the work per day. We know they can finish it in 10 days, thus:

\displaystyle \frac{1}{15}+\frac{1}{N}=\frac{1}{10}

Rearranging:

\displaystyle \frac{1}{N}=\frac{1}{10}-\frac{1}{15}

The LCM of 10 and 15 is 30, thus operating:

\displaystyle \frac{1}{N}=\frac{3-2}{30}=\frac{1}{30}

Solving for N:

N = 30

Y alone can do the piece of work in 30 days.

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