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nikdorinn [45]
2 years ago
12

PLEASE HELP ILL GIVE MEDALS AND MARK BRAINLIEST !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
Korolek [52]2 years ago
8 0

the answer is 0.5. at least that is the answer i got but i could be wrong


Effectus [21]2 years ago
3 0
The probability is 0.5
-Hope it helps!
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***PLEASE HELP I'M TIMED***
Natalija [7]

Answer:

Domain and Range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively

Step-by-step explanation:

We have the functions, f(x) = eˣ and g(x) = x+6

So, their composition will be g(f(x)).

Then, g(f(x)) = g(eˣ) = eˣ+6

Thus, g(f(x)) = eˣ+6.

Since the domain and range of f(x) = eˣ are all real numbers and positive real numbers respectively.

Moreover, the function g(f(x)) = eˣ+6 is the function f(x) translated up by 6 units.

Hence, the domain and range of g(f(x)) are 'All real numbers' and {y | y>6 } respectively.

6 0
2 years ago
Read 2 more answers
1 . What is the distance between the two points. (0,5 1,3), (-0,4, -1,3) ?
Studentka2010 [4]

Answer:

Step-by-step explanation:

x1 = 0.5 x2 = -0.4 y1 = 1.3 y2 = -1.3

\sqrt{(x2 - x1)^{2}+(y2 - y1)^{2}

\sqrt{(-0.4 - 0.5)^{2}+(-1.3 - 1.3)^{2}

=2.75

6 0
3 years ago
(2p + 4) + 5 (p-1) - (p+7)
jonny [76]

<em>Your answer will be, </em><em>"6p - 8"</em>

Thanks,

<em>Deku ❤</em>

6 0
3 years ago
Use the slope-intercept method to graph the equation y=2x-4. Is (3,2) a solution?
Andru [333]
Yes, (3, 2) is a solution to y = 2x - 4. (:
8 0
2 years ago
Read 2 more answers
Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)
givi [52]

Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

Step-by-step explanation:

Since we have given that

y=x^{8sinx}

By using logarithmic on both sides we get,

log y= 8 sinx. logx

(∵ log(a^m)=m.loga)

Now, differentiating on both sides ,we get,

\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})

\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})

\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})

6 0
2 years ago
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