Hi! I don’t know what any of this means but I hope you have an amazing day and I hope god/allah/etc. blesses you :)
sorry I couldn’t answer
Answer:
![\displaystyle\frac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
Step-by-step explanation:
It can work well to identify 4th powers under the radical, then remove them.
![\displaystyle\sqrt[4]{\frac{24x^6y}{128x^4y^5}}=\sqrt[4]{\frac{3x^2}{16y^4}}=\sqrt[4]{\frac{3x^2}{(2y)^4}}\\\\=\frac{\sqrt[4]{3x^2}}{2y}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Csqrt%5B4%5D%7B%5Cfrac%7B24x%5E6y%7D%7B128x%5E4y%5E5%7D%7D%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E2%7D%7B16y%5E4%7D%7D%3D%5Csqrt%5B4%5D%7B%5Cfrac%7B3x%5E2%7D%7B%282y%29%5E4%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B%5Csqrt%5B4%5D%7B3x%5E2%7D%7D%7B2y%7D)
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The applicable rules of exponents are ...
1/a^b = a^-b
(a^b)(a^c) = a^(b+c)
The x-factors simplify as ...
x^6/x^4 = x^(6-4) = x^2
The y-factors simplify as ...
y/y^5 = 1/y^(5-1) = 1/y^4
The constant factors simplify in the usual way:
24/128 = (8·3)/(8·16) = 3/16
19 27 28 29 30 315 64 29 46 is the
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This question is quite simple really. They are basically asking you to combine like terms. You have two different figures with the variable y, so you just combine the them. It would then be 3x + 2y. You cannot simplify this equation any further since there is nothing to solve for or anymore like terms to combine.