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Vera_Pavlovna [14]
3 years ago
8

Please help me with this function on a closed interval!

Mathematics
1 answer:
Softa [21]3 years ago
5 0

Answer:

(E) 13

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Antiderivatives - Integrals

Integration Rule [Fundamental Theorem of Calculus 1]:                                      \displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)

Integration Rule [Fundamental Theorem of Calculus 2]:                                     \displaystyle \frac{d}{dx}[\int\limits^x_a {f(t)} \, dt] = f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \int\limits^4_0 {f'(t)} \, dt = 8<u />

<u />\displaystyle f(4) = \text{unknown}<u />

<u />

<u>Step 2: Integrate</u>

  1. [Integral] Evaluate [Integration Rule - FTC 1 and 2]:                                     \displaystyle \int\limits^4_0 {f'(t)} \, dt = f(4) - f(0)
  2. [Integral] Substitute in variables [Given/Table]:                                           \displaystyle 8 = f(4) - 5
  3. [Addition Property of Equality] Isolate f(4):                                                   \displaystyle 13 = f(4)
  4. Rewrite:                                                                                                           \displaystyle f(4) = 13

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

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The number of time it would take Todd to paint the room alone is 15 hours.

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To calculate the number of time it would take Todd to paint the room alone:

How to solve a word problem:

In order to solve this exercise, we would first of all calculate their individual rate and combined rate respectively. Finally, we would add their individual rates together and equate it to the combined rate.

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Rate = \frac{1}{10} \;work/hr

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Rate = \frac{1}{12} \;work/hr

<u>For </u><u>Todd</u><u>:</u>

Rate = \frac{1}{t} \;work/hr

<u>Combined rate:</u>

Rate = \frac{1}{4} \;work/hr

Adding the individual rates, we have:

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2 years ago
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marishachu [46]
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r=[f(2)-f(0)]/(2-0)
r=[f(2)-f(0)]/2

1) First function: h(x)
r=[h(2)-h(0)]/2
x=2→h(2)=(2)^2+2(2)-6
h(2)=4+4-6
h(2)=2
x=0→h(0)=(0)^2+2(0)-6
h(0)=0+0-6
h(0)=-6
r=[h(2)-h(0)]/2
r=[2-(-6)]/2
r=(2+6)/2
r=(8)/2
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2) Second function: f(x)
A function, f, has an
x-intercept at (2,0)→x=2, f(2)=0
and a y-intercept at (0,-10)→x=0, f(0)=-10
r=[f(2)-f(0)]/2
r=[0-(-10)]/2
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r=(10)/2
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3) Third function: g(x)
r=[g(2)-g(0)]/2
From the graph:
g(2)=6
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4) Fourth function: j(x)
r=[j(2)-j(0)]/2
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x=2→j(2)=-8
x=0→j(0)=4
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Answer:
Pairs
1) h(x)     4
2) f(x)      5
3) g(x)     2
4) j(x)     -6
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