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Alik [6]
3 years ago
14

Help me with this question pls pls pls

Mathematics
1 answer:
34kurt3 years ago
6 0

Answer:

Check pdf

Step-by-step explanation:

Download pdf
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12 in.<br>11 in.<br>17 in.<br>16 in. -​
Jet001 [13]

Answer:

  16. 216 square inches

  18. 252 square cm

Step-by-step explanation:

16. The figure can be decomposed into a 12×17 rectangle and a triangle with base 16-12=4 and height 17-11=6.

Then the area is ...

  rectangle area = 12×17 = 204

  triangle area = (1/2)(4×6) = 12

  total area = rectangle area + triangle area = 204 +12 = 216 . . . square inches

__

18. The figure can be decomposed into a 12×12 square and a 18×6 rectangle. Then the total area is ...

  area = 12×12 + 18×6 = 252 . . . square cm

7 0
3 years ago
Find the value of each variable
lana66690 [7]
I know y is 120 but idk what x is
4 0
3 years ago
At which values of x does the function F(x) have a vertical asymptote ? Check all that apply. (Picture provided )
Paul [167]
The answers are -3 and -2

Hope this helped (:
7 0
3 years ago
Read 2 more answers
Did I do this right????
Svetlanka [38]

Answer:

x = -7, y = -3 yup you did it right!

Step-by-step explanation:

Solve the following system:

{-2 y + x = -1 | (equation 1)

8 y - 5 x = 11 | (equation 2)

Swap equation 1 with equation 2:

{-(5 x) + 8 y = 11 | (equation 1)

x - 2 y = -1 | (equation 2)

Add 1/5 × (equation 1) to equation 2:

{-(5 x) + 8 y = 11 | (equation 1)

0 x - (2 y)/5 = 6/5 | (equation 2)

Multiply equation 2 by 5/2:

{-(5 x) + 8 y = 11 | (equation 1)

0 x - y = 3 | (equation 2)

Multiply equation 2 by -1:

{-(5 x) + 8 y = 11 | (equation 1)

0 x + y = -3 | (equation 2)

Subtract 8 × (equation 2) from equation 1:

{-(5 x) + 0 y = 35 | (equation 1)

0 x + y = -3 | (equation 2)

Divide equation 1 by -5:

{x + 0 y = -7 | (equation 1)

0 x + y = -3 | (equation 2)

Collect results:

Answer: {x = -7, y = -3

4 0
2 years ago
State the amplitude and period of f(t) = -0.3sin t/3
OLga [1]

Answer:

Amplitude is 0.3; period is 6π

Step-by-step explanation:

The amplitude is |-0.3| = 0.3.

The period and frequency are related through

                   2π

period  =  ----------

                     b

where b is the coefficient of the independent variable; here that coefficient is 1/3.

Thus, the period here is found using b = 1/3:

period = 2π/b, or 2π/(1/3), or 6π

5 0
3 years ago
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