Quickly IT is Due an a hour PLease show work show me how to do it and No links
1 answer:
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Solution :
The objective of the study is to test the claim that the loaded die behaves at a different way than a fair die.
Null hypothesis,
That is the loaded die behaves as a fair die.
Alternative hypothesis, : loaded die behave differently than the fair die.
Number of attempts , n = 200
Expected frequency,
Test statistics,
≈ 5.8
Degrees of freedom, df = n - 1
= 6 - 1
= 5
Level of significance, α = 0.10
At α = 0.10 with df = 5, the critical value from the chi square table
= 9.236
Thus the critical value is
= chi dist (5.80, 5)
= 0.3262
Decision : The value of test statistics 5.80 is not greater than the critical value 9.236, thus fail to reject at 10% LOS.
Conclusion : There is no enough evidence to support the claim that the loaded die behave in a different than a fair die.
Answer:
56 lb
Step-by-step explanation:
84-28=56
For proof look at the calculator. Calculator never lies. UwU
