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vovikov84 [41]
3 years ago
11

Pls help ASAP!!!

Mathematics
1 answer:
marissa [1.9K]3 years ago
3 0

240 children and 382 adult swam at the public pool that day

<em><u>Solution:</u></em>

Let "c" be the number of childrens

Let "a" be the number of adults

Cost of 1 child ticket = $ 1.75

Cost of 1 adult ticket = $ 2.50

<em><u>622 people used the public swimming pool</u></em>

Therefore,

number of childrens + number of adults = 622

c + a = 622 ------ eqn 1

<em><u>The receipts for admission totaled $ 1375.00</u></em>

Therefore, we can frame a equation as:

number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00

c \times 1.75 + a \times 2.50 = 1375

1.75c + 2.50a = 1375 ----- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 1,

c = 622 - a -------- eqn 3

<em><u>Substitute eqn 3 in eqn 2</u></em>

1.75(622 - a) + 2.50a = 1375

1088.5 - 1.75a + 2.50a = 1375

0.75a = 1375 - 1088.5

0.75a = 286.5

a = 382

<em><u>Substitute a = 382 in eqn 3</u></em>

c = 622 - 382

c = 240

Thus 240 children and 382 adult swam at the public pool that day

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