Pls help ASAP!!!
1 answer:
240 children and 382 adult swam at the public pool that day
<em><u>Solution:</u></em>
Let "c" be the number of childrens
Let "a" be the number of adults
Cost of 1 child ticket = $ 1.75
Cost of 1 adult ticket = $ 2.50
<em><u>622 people used the public swimming pool</u></em>
Therefore,
number of childrens + number of adults = 622
c + a = 622 ------ eqn 1
<em><u>The receipts for admission totaled $ 1375.00</u></em>
Therefore, we can frame a equation as:
number of childrens x Cost of 1 child ticket + number of adults x Cost of 1 adult ticket = 1375.00
1.75c + 2.50a = 1375 ----- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
c = 622 - a -------- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
1.75(622 - a) + 2.50a = 1375
1088.5 - 1.75a + 2.50a = 1375
0.75a = 1375 - 1088.5
0.75a = 286.5
a = 382
<em><u>Substitute a = 382 in eqn 3</u></em>
c = 622 - 382
c = 240
Thus 240 children and 382 adult swam at the public pool that day
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<h2>Hello!</h2>
The answer is:
The third option:
2.7 times as much.
<h2>Why?</h2>To calculate how many more juice will the new can hold, we need to calculate the old can volume to the new can volume.
So, calculating we have:
Old can:
Since the cans have a right cylinder shape, we can calculate their volume using the following formula:
Where,
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So, calculating the volume, we have:
We have that the volume of the old can is:
New can:
We are given the new can dimensions, the diameter is increased but the height is the same, so:
Calculating we have:
Now, dividing the volume of the new can by the old can volume to know how many times more juice will the new can hold, we have:
Hence, we have that the new can hold 2.7 more juice than the old can, so, the answer is the third option:
2.7 times as much.
Have a nice day!