All categories

3 years ago

When the function ƒ(x) = 4x−2 is evaluated for x = 3, the output is: -4 -6 -16 -none

Mathematics

1 answer:

Mkey [24]3 years ago

7 0

Answer:

None

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

f(x) = 4x - 2

x = 3

Step 2: Evaluate

Substitute in x [Function]: f(3) = 4(3) - 2
Multiply: f(3) = 12 - 2
Subtract: f(3) = 10

You might be interested in

A fitness center currently has 320 members. Monthly membership fees are $45. The manager of the fitness center has determined th

Vladimir [108]

I thinks it’s a because it’s

3 0

3 years ago

Which survey best represents a sampling error?

Scorpion4ik [409]

Answer:

a survey of L.A. musicians taken to determine their favorite type of breakfast cereal

Step-by-step explanation:

because all of the surveyed were asked questions that were related to what the do. Musicians and cereal have nothing to do with each other.

Hope this helps. If it does, can i have brainliest?

7 0

2 years ago

Read 2 more answers

Help with question 4 please

Juliette [100K]

Answer: y=5 x=11

abc=def

ab=de <b=<e

17y-8=12+13y 11x-4=117

-13y -13y +4 +4

4y-8=12 11/11x=121/11

+8 +8 x=11

4/4y=20/4

y=5

7 0

3 years ago

A study was conducted to determine whether magnets were effective in treating pain. The values represent measurements of pain us

amm1812

Answer:

Given:

Sham: n= 20, x=0.44, s=1.24,

Magnet:n= 20, x =0.49, s= 0.95

For Sham:

Sample size, n = 20

Sample mean = 0.44

Standard deviation = 1.24

For Magnet:

Sample size = 20

Sample mean = 0.49

Standard deviation = 0.95

The null and alternative hypotheses:

H0: s1²=s2²

H1: s1² ≠ s2²

a) To find the test statistics, use the formula:

$\frac{s1^2}{s2^2}$

$\frac{1.24^2}{0.95^2} = \frac{1.5376}{0.9025} = 1.7037$

Test statistics = 1.7037

b) P-value:

Sham: degrees of freedom $= n - 1 = 20 - 1 = 19$

Magnet: degrees of freedom $= n - 1 = 20 - 1 = 19$

The critical values:

[Za/2, df1, df2)], [(1 - Za/2), df1, df2]

$f[0.05/2, 19, 19], f[(1 - 0.05/2), 19, 19]$

$f[0.025, 19, 19], f[0.975, 19, 19]$

$(2.526, 0.3958)$

The rejection region:

Reject H0, if F < 0.3958 or if F > 2.526

c) Conclusion:

Since the critical values of test statistic is between (0.3958 < 1.7037 < 2.526), we fail to reject null hypothesis H0.

There is insufficient evidence to to support the claim that those given a sham treatment have reductions that vary more than those treated with magnets

3 0

3 years ago

One serving of a certain brand of yogurt contains 9 g of fat. The low-fat version contains 36.75% less fat per serving. How ma

slava [35]

Answer:

Answer Choices??

Step-by-step explanation:

5 0

3 years ago