Answer:
The answers are a) 1/3 and b) 1/3
Step-by-step explanation:
we will consider t to be the arrival time variable in minutes. We will have it run from 0 min to 30 min omitting the 7 hours , which won't change the results since the PDF we are about to calculate is a constant.
So the PDF of the arrival time is a constant and the since the area under this PDF distribution should be equal to 1 so, Let the height of the constant distribution equal to c, so c*30 (which is equal to the total probability) would be the area under the distribution, but this area should be equal to 1, So that gives us c=1/30 which is the value of the constant PDF for all corresponding arrival times.
part a) of the question asks for the probability that the passengers wait less than 5 minute. The passengers would have to wait for the bus 5 min or late if they arrive between the times (10 - 15 )min and (25 - 30) min. So we will have to integrate the PDF corresponding to these times and then we will will just have to add the probabilities calculated as give below,

Now part b) of the question asks for the probability that the passenger waits for more than 10 minutes. Which can be calculated by noting that that can only happen if the passenger arrives between the times (0 - 5) min and (15 - 20) min. So we will have to integrate the PDF corresponding to these times and then we will will just have to add the probabilities calculated as give below,

The answer to part b) is 1/3.
B
If two lines have the same slope and different intercepts, then they will never cross each other; they are parallel lines. Therefore, they have no solutions since a solution is where the lines cross.
Answer:
3:1
Step-by-step explanation:
Answer:
Sorry :( I would help but I'm not very good at this type of math =c
Step-by-step explanation:
I hope someone will see this :D
Answer:
y=4/3x-1/3
Step-by-step explanation:
m=y2-y1/x2-x1
fill in the two points for the y's and the x's
then proceed to y = mx+b
Where:
m is the slope, and
b is the y-intercept
then you solve and <u>bam</u>!