Answer:
The correct answer to the following question will be 2. the operator new.
Explanation:
New operator is used to allocating the memory to the instance object.The new object can be created by using a "new" keyword in java .
Syntax of using 'new' operator is :
class_name object_name=new class_name() // it allocated the memory to the class
For Example :
ABC obj = new ABC;
Now, this time obj points to the object of the ABC class.
obj = new ABC ();
call the construction of ABC class
Records for the first one and table for the second one
Answer:
In C++:
#include <bits/stdc++.h>
#include <iostream>
#include <vector>
using namespace std;
int main(){
vector<int> vectItems;
cout << "Vector length: ";
int ln; cin>>ln;
int num;
for (int ikk = 0; ikk < ln; ikk++){
cin >> num;
vectItems.push_back(num);}
int small, secsmall;
small = secsmall = INT_MAX;
for (int ikk = 0; ikk < ln; ikk++){
if(vectItems[ikk] < small){
secsmall = small;
small = vectItems[ikk]; }
else if (vectItems[ikk] < secsmall && vectItems[ikk] != small) {
secsmall = vectItems[ikk];} }
cout<<small<<" "<<secsmall;
return 0;}
Explanation:
See attachment for program file where comments are used for explanation
Answer:
Answer explained below
Explanation:
void bubbleSort(int X[], int Y[], int n)
{
int i, j;
for (i = 0; i < n-1; i++)
// Last i elements are already in place
for (j = 0; j < n-i-1; j++)
if (X[j] > X[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
if (X[j] == X[j+1]&&Y[j]<Y[j+1])
{
swap(X[j],X[j+1])
swap(Y[j],Y[j+1]);
}
}
Since the above algorithm contains 2 nested loops over n.
So, it is O(n^2)
