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inn [45]
3 years ago
8

Alexia is 13 years old. Camden is 11 years younger than Alexia and Jane is 1 years younger

Mathematics
1 answer:
mario62 [17]3 years ago
5 0

Answer:

Jane is 1 years old.

Step-by-step explanation:

13 - 11 = 2

2 - 1 = 1

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LMNP is roatated 90 degrees clockwise around the origin
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It would be c, (1, 0)

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5. Find the discriminant of 15x2 = 4x – 1 and describe
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Answer:

a) The discriminant of the equation =  - 44

b)The nature of the roots will be imaginary.

c) x = \frac{2 +\sqrt{11} i}{15}  or, x = \frac{2 - \sqrt{11} i}{15}

Step-by-step explanation:

Here, the given expression is 15x^{2}  = 4x -1

or, 15x^{2}  -  4x + 1   = 0

Now the discriminant (D) of a quadratic equation ax^{2}  +b x + c   = 0

D = b^{2}   -  4ac  = (-4)^{2}  -  4(15) (1)  = 16 - (60) = -44

Hence, the discriminant of the equation =  - 44

As D< 0, so the roots will be imaginary.

Now,by quadratic formula : x = \frac{-b \pm \sqrt{b^{2}  - 4ac} }{2a}

So, here x = \frac{-(-4) \pm \sqrt{D} }{2a}  = \frac{4 \pm \sqrt{(-44 )} }{30}

So, either x = \frac{4 + \sqrt{(-44 )} }{30} or, x =  \frac{4 - \sqrt{(-44 )} }{30}

or, x = \frac{2 +\sqrt{11} i}{15}  or, x = \frac{2 - \sqrt{11} i}{15}

8 0
3 years ago
Can someone please help me with this?
valentina_108 [34]

Answer:

L: 110 W: 90

Step-by-step explanation:

110 + 110 + 90 + 90=400 (perimeter)

110 x 90 =9900 (new area that is greater than the original)

ding ding.

also this was not worth only five pts man LOL

3 0
3 years ago
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729, <span>â6561 is the answer</span>
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3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp
Zarrin [17]

Answer:

(\frac{1}{2}, 2)

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Using the midpoint formula, M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}), we can find the coordinates that represents the position of the ship at noon.

Let L(-4, 7) = (x_1, y_1) (given on the coordinate plane)

B(5, -3) = (x_2, y_2) (given also)

Plug in the values into the formula and solve as follows:

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M(\frac{1}{2}, \frac{7 - 3}{2})

M(\frac{1}{2}, \frac{4}{2})

M(\frac{1}{2}, 2)

Position of the ship at noon is best represented at (\frac{1}{2}, 2)

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4 years ago
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