A bag contains 10 blue, 6 green, and 4 red marbles. You choose a marble with one hand and then a second marble with the other ha
nd. What is the probability that you will first choose a red marble followed by a green marble?
2 answers:
I would say 6/98.
Hope this helped!
The bag contains 10+6+4=20 marbles, so the probability of selecting a red then a green in that order without replacement is:
(4/20)(6/19)=24/380
6/95 (≈6.32%)
You might be interested in
Answer:
1/3
Step-by-step explanation:
There are 6 sides on a dice. These are two of the possibilities. 2/6 is the same as 1/3.
Answer:
20 servings of 100-milliliter sports drink
Step-by-step explanation:
43 tens = 43 * 10 = 430
3 tens = 3 * 10 = 30
430 x 30 = 12900 tens
12900/100 = 129 hundreds <===
Answer:
Step-by-step explanation:
1. 5
2. -9
3. -4
4. 4 > .25
5. 0.142 < 7
6. -8 = -8
The answer is A, look at the difference between 0 and 15 (15) and the difference between 5 and 10 (5) then divide them 5/15.