A bag contains 10 blue, 6 green, and 4 red marbles. You choose a marble with one hand and then a second marble with the other ha
nd. What is the probability that you will first choose a red marble followed by a green marble?
2 answers:
I would say 6/98.
Hope this helped!
The bag contains 10+6+4=20 marbles, so the probability of selecting a red then a green in that order without replacement is:
(4/20)(6/19)=24/380
6/95 (≈6.32%)
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