The first two consecutive odd integers are 1 and 3.
The height has to be 3 since the question implies that the height is exceeds the base. So the base is 1. b = 1 cm
The area of a triangle is base*height*(1/2)
Plug in the values for base and height.
1*3*(1/2)
Simplify. Your final answer should be 1.5 cm^2
Answer: pass 12 fail 12 passes 15 fail1 3
Step-by-step explanation:
pass 12 fail 12
pass 15 fail 13
Answer:
c=0
Step-by-step explanation:
ATQ a.b=|a||b|sin(45)
1+c=sqrt(1+c^2)*sqrt(2)*1/sqrt(2)
1+c=sqrt(1+c^2)
(1+c)^2=(1+c^2)
2c=0, c=0
Dimensions of the room in cm = 2.54 x 12 by 15 x 2.54 by 2.54 x 8.5 = 30.48 by 38.1 by 21.59
Volume of the room in cubic cm = 30.48 x 38.1 x 21.59 cubic cm = 25,072.21 cubic cm
Given that the density of air at room temperature is

, thus the mass of air in the room = 25,072.21 x 0.00118 = 29.59 g = 0.0296 kg
Given that the lethal dose of HCN is approximately 300 mg HCN per kilogram of air when inhaled, thus the <span>amount of HCN that gives the lethal dose in the small laboratory room is given by 300 x 0.0296 =
8.88 mg.</span>
It would be 7.54 because you fist have to put the numbers ordered smallest to biggest amount 7.15, 7.44, 7.48,7.60, 7.72, 7.73 so the numbers that are in the middle are 7.48 and 7.60 you add them up, and the result you divide by 2 which gives you 7.54.