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lisabon 2012 [21]
3 years ago
11

The length of a rectangle is shown below: On a coordinate grid from negative 6 to positive 6 on the x-axis and on the y-axis, tw

o points A and B are shown. The point A is on ordered pair 1, 2, and the point B is on ordered pair negative 3, 2. A straight line joins the points A and B. If the area of the rectangle to be drawn is 12 square units, where should points C and D be located, if they lie vertically below the line that connects B and A, to make this rectangle? C(−3, −2), D(1, −2) C(−3, −1), D(1, −1) C(−3, −4), D(1, −4) C(−3, −5), D(1, −5)
Mathematics
1 answer:
sukhopar [10]3 years ago
4 0

Answer:

<em>Would be the answer D(1, −4)  </em>

Step-by-step explanation:

<em>Excuse me if i'm wrong, it seems like you have the same test or almost. And this was the answer on mine. I hope it works out for you!</em>

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cosx=14/49

x=cos-¹(14/49)=73.4

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2 years ago
Use the information in the table to find the constant rate<br> of change in dollars per hour
Debora [2.8K]

Answer:

It goes up $9 per hour

Step-by-step explanation:

5 0
3 years ago
CAN YOU HELP ME WITH THIS​
____ [38]

the sum of the expanded angle is 180⇒

40+40+2x+30=180\\2x=70\\x=35

8 0
3 years ago
Read 2 more answers
PLEASE HELP!! I’m very confuse
SVETLANKA909090 [29]

Given:

A(16, 4)

B(34, 40)

Line segment AB partition in the ratio 1 : 5.

To find:

The coordinate of a point that partitions AB.

Solution:

Section formula:

$P(x,y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+m y_{1}}{m+n}\right)

Here x_1=16, y_1=4, x_2=34, y_2=40 and m = 1, n = 5

$P(x,y)=\left(\frac{1\times 34+5 \times 16}{1+5}, \frac{1\times 40+5 \times4}{1+5}\right)

$P(x,y)=\left(\frac{ 34+80}{6}, \frac{40+20}{6}\right)

$P(x,y)=\left(\frac{ 114}{6}, \frac{60}{6}\right)

$P(x,y)=(19, 10)

The coordinate of point that partitions the segment AB is (19, 10).

4 0
3 years ago
How do you do this question?
IRINA_888 [86]

Answer:

∑ (-1)ⁿ⁺³ 1 / (n^½)

∑ (-1)³ⁿ 1 / (8 + n)

Step-by-step explanation:

If ∑ an is convergent and ∑│an│is divergent, then the series is conditionally convergent.

Option A: (-1)²ⁿ is always +1.  So an =│an│and both series converge (absolutely convergent).

Option B: bn = 1 / (n^⁹/₈) is a p series with p > 1, so both an and │an│converge (absolutely convergent).

Option C: an = 1 / n³ isn't an alternating series.  So an =│an│and both series converge (p series with p > 1).  This is absolutely convergent.

Option D: bn = 1 / (n^½) is a p series with p = ½, so this is a diverging series.  Since lim(n→∞) bn = 0, and bn is decreasing, then an converges.  So this is conditionally convergent.

Option E: (-1)³ⁿ = (-1)²ⁿ (-1)ⁿ = (-1)ⁿ, so this is an alternating series.  bn = 1 / (8 + n), which diverges.  Since lim(n→∞) bn = 0, and bn is decreasing, then an converges.  So this is conditionally convergent.

5 0
3 years ago
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