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posledela
3 years ago
8

Michael has five different stocks that he watches on a daily basis. The table shows the change in each stock price in dollars at

the end of a trading day. Change in Daily Stock Prices (Dollars) Stock A Stock B Stock C Stock D Stock E –1.5 2.9 Negative one-half 3 and three-fourths 4.6 A number line going from negative 6 to positive 6 in increments of 1. What is the correct order of the rational numbers in the table from least to greatest? Use the number line to help you. –1.5, 2.9, Negative one-half, 3 and three-fourths, 4.6 Negative one-half, –1.5, 2.9, 3 and three-fourths, 4.6 –1.5, Negative one-half, 2.9, 3 and three-fourths, 4.6 4.6, 3 and three-fourths, 2.9, Negative one-half, –1.5
Mathematics
1 answer:
ddd [48]3 years ago
3 0

Answer:

1256789

Step-by-step explanation:

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The length of a rectangle is two more than the width. the perimeter is 36cm. write a system of equations that could be used to d
mel-nik [20]
If the length is two times its width and its perimeter is 36cm. we can write the following equation
let the width be X.
so the equation will be:
(X + 2X)2=36cm or
2X + 4X=36cm
3 0
3 years ago
I keep getting kicked off of Brainly when other tutors go to try and answer this question.
Ilya [14]

Answer

(C) 15

Explanation

The given equation that represents the number of bags of sand (x) and bags of mulch (y) that can be bought with $105 is

3x+7y=105

If no bags of sand are bought, therefore x = 0

Then the number of bags of mulch that can be bought with $105 will be

\begin{gathered} 3(0)+7y=105 \\  \\ 0+7y=105 \\  \\ 7y=105 \\  \\ y=\frac{105}{7} \\  \\ y=15 \end{gathered}

8 0
1 year ago
50 POINTS! + BRAINLIEST! ANSWER ASAP
Llana [10]
C it is 1,-6 jjjjjjjjj
5 0
2 years ago
Read 2 more answers
For what values of x is f(x) = |x + 1| differentiable? I'm struggling my butt off for this course
pav-90 [236]

By definition of absolute value, you have

f(x) = |x+1| = \begin{cases}x+1&\text{if }x+1\ge0 \\ -(x+1)&\text{if }x+1

or more simply,

f(x) = \begin{cases}x+1&\text{if }x\ge-1\\-x-1&\text{if }x

On their own, each piece is differentiable over their respective domains, except at the point where they split off.

For <em>x</em> > -1, we have

(<em>x</em> + 1)<em>'</em> = 1

while for <em>x</em> < -1,

(-<em>x</em> - 1)<em>'</em> = -1

More concisely,

f'(x) = \begin{cases}1&\text{if }x>-1\\-1&\text{if }x

Note the strict inequalities in the definition of <em>f '(x)</em>.

In order for <em>f(x)</em> to be differentiable at <em>x</em> = -1, the derivative <em>f '(x)</em> must be continuous at <em>x</em> = -1. But this is not the case, because the limits from either side of <em>x</em> = -1 for the derivative do not match:

\displaystyle \lim_{x\to-1^-}f'(x) = \lim_{x\to-1}(-1) = -1

\displaystyle \lim_{x\to-1^+}f'(x) = \lim_{x\to-1}1 = 1

All this to say that <em>f(x)</em> is differentiable everywhere on its domain, <em>except</em> at the point <em>x</em> = -1.

4 0
3 years ago
What are two ways to find the slope of a line?​
DedPeter [7]

Answer:

m = (y - y)/(x - x)

Rise/run

Step-by-step explanation:

4 0
2 years ago
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